bash-5.1 distribution sources and documentation

[thirdparty/bash.git] / tests / nameref4.sub

#   This program is free software: you can redistribute it and/or modify
#   it under the terms of the GNU General Public License as published by
#   the Free Software Foundation, either version 3 of the License, or
#   (at your option) any later version.
#
#   This program is distributed in the hope that it will be useful,
#   but WITHOUT ANY WARRANTY; without even the implied warranty of
#   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
#   GNU General Public License for more details.
#
#   You should have received a copy of the GNU General Public License
#   along with this program.  If not, see <http://www.gnu.org/licenses/>.
#
# test suite cribbed from ksh93 nameref tests
typeset -i errors=0
ckval()
{
	typeset -n one=$1

	if [[ $one != $2 ]]; then
		echo "one=$one != 2=$2"
		(( errors++ ))
	fi
}
		
ckref()
{
	typeset -n one=$1 two=$2

	if [[ $one != $two ]]; then
		echo "one=$one != two=$two"
		(( errors++ ))
	fi
}

name=first

ckref name name

func1()
{
        typeset -n color=$1
        func2 color
}

func2()
{
        typeset color=$1
        set -- ${color[@]}
        printf "<%s>" "$@"
	echo
}

typeset -A color
color[apple]=red
color[grape]=purple
color[banana]=yellow

# XXX
#func1 color

unset foo bar
export bar=foo
typeset -n foo=bar
ckval foo foo

# XXX - need to see if we can do checks for self-referencing at assignment
# time
command typeset -n xx=yy
command typeset -n yy=xx
echo $?

unset foo bar
unset -n foo bar
set foo
typeset -n bar=$1
foo=hello
ckval bar hello

# XXX -- another self-referencing error?
# ksh93 makes this another invalid self-reference
unset foo
unset -n bar

bar=123
foobar()
{
	typeset -n foo=bar
	typeset -n foo=bar

	ckval foo 123
}

typeset -n short=long
short=( a b )
echo "expect <a b>"
echo ${long[@]}
unset long
unset -n short

# assignment to a previously-unset variable
typeset -n short=long
short=foo
echo "expect <foo>"
echo ${long}
unset long
unset -n short

unset foo bar

# simple array references and assignments
typeset -n foo=bar
bar=( 1 3 5 7 9)
echo ${foo[@]}
echo ${foo[4]}
foo[2]=42
echo ${bar[@]}

barfunc()
{
	typeset -n v=$1
	echo ${v[@]}
	echo ${v[4]}
	v[2]=44
	echo ${bar[@]}
}
barfunc bar

unset -f foobar
unset bar
unset -n foo

# should ref at global scope survive call to foobar()?
unset ref x
typeset -n ref
x=42
foobar()
{
	local xxx=3
	ref=xxx
	return 0
}
echo ${ref-unset}
ref=x
foobar
ckval ref xxx
ckval x xxx

# assignment in a function to something possibly out of scope
assignvar()
{
	typeset -n v=$1
	shift
	v="$@"
}

assignvar lex a b c d e
echo "expect <a b c d e>"
recho "${lex}"

unset foo bar short long

typeset -n foo='x[2]'

x=(zero one two three four)
foo=seven

echo "expect <zero> <one> <seven> <three> <four>"
recho "${x[@]}"

unset ref x
unset -n ref

typeset -n ref
ref=x
# make sure nameref to a previously-unset variable creates the variable
ref=42
ckval x 42

# make sure they work inside arithmetic expressions
unset foo bar ref x xxx
unset -n ref

typeset -i ivar
typeset -n iref=ivar

ivar=4+3
ckval ivar 7
iref+=5
ckval ivar 12
echo $(( iref+4 ))
(( iref=17 ))
ckval ivar 17

typeset +n iref
unset iref ivar

typeset +n foo bar
unset foo bar

# should the reference do immediate evaluation or deferred?
set -- one two three four
bar=4
# XXX - what does foo get set to here?
typeset -n foo='bar[0]'
echo "expect <4>"
echo ${bar[0]}
echo "expect <4>"
echo ${foo}
echo "expect <4>"
echo $foo
ckval foo $bar

# Need to add code and tests for nameref to array subscripts
bar=(one two three four)

typeset -n foo='bar[0]'
typeset -n qux='bar[3]'
echo "expect <one>"
echo ${bar[0]}
echo "expect <one>"
echo ${foo}
echo "expect <one>"
echo $foo
ckval foo $bar

echo "expect <four>"
echo $qux
ckval qux ${bar[3]}

# Need to add code and tests for `for' loop nameref variables

echo errors = $errors
exit $errors