[gdb] Don't set initial language using previous language
When language is set to auto, part of loading an executable is to update the
language accordingly. This is implemented by set_initial_language.
In case of a c++ executable without DW_AT_main_subprogram,
set_initial_language finds "main" in the minimal symbols, and does a lookup of
"main" in the symbol tables to determine the language of the symbol, and uses
that as initial language.
The symbol lookup is done using lookup_symbol which is a wrapper around
lookup_symbol_in_language, using the current language.
So, consider two c++ executables a.out and b.out, which we'll load one after
another. If we track the resulting lookup_symbol_in_language calls:
...
$ gdb -batch \
-ex "b lookup_symbol_in_language" \
-ex r -ex c -ex c \
--args gdb
...
we find that indeed lookup_symbol_in_language is called once using language_c, and
once using language_c_plus:
...
(gdb) file a.out
Reading symbols from a.out...
Breakpoint 1, lookup_symbol_in_language (name=0x5555568c2050 "main", \
block=0x0, domain=VAR_DOMAIN, lang=language_c, is_a_field_of_this=0x0) \
at ../../gdb/symtab.c:1905
1905 {
(gdb) file b.out
Load new symbol table from "b.out"? (y or n) y
Reading symbols from b.out...