Fix SQUID_YESNO 'syntax error near unexpected token' (#2117)

[thirdparty/squid.git] / src / auth / basic / Scheme.cc

/*
 * Copyright (C) 1996-2025 The Squid Software Foundation and contributors
 *
 * Squid software is distributed under GPLv2+ license and includes
 * contributions from numerous individuals and organizations.
 * Please see the COPYING and CONTRIBUTORS files for details.
 */

#include "squid.h"
#include "auth/basic/Config.h"
#include "auth/basic/Scheme.h"
#include "debug/Messages.h"
#include "debug/Stream.h"
#include "helper.h"

Auth::Scheme::Pointer Auth::Basic::Scheme::_instance = nullptr;

Auth::Scheme::Pointer
Auth::Basic::Scheme::GetInstance()
{
    if (_instance == nullptr) {
        _instance = new Auth::Basic::Scheme();
        AddScheme(_instance);
    }
    return _instance;
}

char const *
Auth::Basic::Scheme::type() const
{
    return "basic";
}

void
Auth::Basic::Scheme::shutdownCleanup()
{
    if (_instance == nullptr)
        return;

    _instance = nullptr;
    debugs(29, Critical(12), "Shutdown: Basic authentication.");
}

Auth::SchemeConfig *
Auth::Basic::Scheme::createConfig()
{
    Auth::Basic::Config *newCfg = new Auth::Basic::Config;
    return dynamic_cast<Auth::SchemeConfig*>(newCfg);
}