#!/bin/sh

PYTHON=$(which python 2>/dev/null)

if [ -z "${PYTHON}" ]; then
	# Python is not present. Fail silently.
	exit 0
fi

files=""
for i in $*; do
	if [ -e ${i}c ] && [ -e ${i}o ]; then
		continue # all files we want are already there
	fi
	files="$files $i"
done

if [ -z "${files}" ]; then
	# No files need to be proceeded.
	exit 0
fi

$PYTHON -c "
import sys, os, string, py_compile

files = '''$files'''
print 'Byte-compiling python modules...'
for file in string.split(files):
    if not os.path.exists(file) or not (len(file) >= 3 and file[-3:] == '.py'):
        continue
    print file,
    sys.stdout.flush()
    py_compile.compile(file)
print" || exit $?

# this will fail for python < 1.5, but that doesn't matter ...
$PYTHON -O -c "
import sys, os, string, py_compile

files = '''$files'''
print 'Byte-compiling python modules (optimised versions) ...'
for file in string.split(files):
    if not os.path.exists(file) or not (len(file) >= 3 and file[-3:] == '.py'):
        continue
    print file,
    sys.stdout.flush()
    py_compile.compile(file)
print" 2>/dev/null || :