i386: fix ix86_hardreg_mov_ok with lra_in_progress

i386: fix ix86_hardreg_mov_ok with lra_in_progress

Originally eliminate_regs_in_insnit will transform
(parallel [
  (set (reg:QI 130)
    (plus:QI (subreg:QI (reg:DI 19 frame) 0)
      (const_int 96)))
  (clobber (reg:CC 17 flag))]) {*addqi_1}
to
(set (reg:QI 130)
 (subreg:QI (reg:DI 19 frame) 0)) {*movqi_internal}
when verify_changes.

But with No Flags add, it transforms
(set (reg:QI 5 di)
  (plus:QI (subreg:QI (reg:DI 19 frame) 0)
   (const_int 96))) {*addqi_1_nf}
to
(set (reg:QI 5 di)
 (subreg:QI (reg:DI 19 frame) 0)) {*addqi_1_nf}.
there is no extra clobbers at the end, and
its dest reg just is a hardreg. For ix86_hardreg_mov_ok,
it returns false. So it fails to update insn and causes
the ICE when transform to movqi_internal.

But actually it is ok and safe for ix86_hardreg_mov_ok
when lra_in_progress.

And tested the spec2017, the performance was not affected.

gcc/ChangeLog:

	* config/i386/i386.cc (ix86_hardreg_mov_ok): Relax
	hard reg mov restriction when lra in progress.