The interval_tree_subtree_search() holds the loop invariant:
start <= node->ITSUBTREE
Let's say we have a following tree:
node
/ \
left right
So we know node->ITSUBTREE is contributed by one of the following:
* left->ITSUBTREE
* ITLAST(node)
* right->ITSUBTREE
When we come to the right node, we are sure the first two don't
contribute to node->ITSUBTREE and it must be the right node does the
job.
So skip the check before go to the right subtree.
Link: https://lkml.kernel.org/r/20250310074938.26756-7-richard.weiyang@gmail.com
Signed-off-by: Wei Yang <richard.weiyang@gmail.com>
Cc: Matthew Wilcox <willy@infradead.org>
Cc: Michel Lespinasse <michel@lespinasse.org>
Cc: Jason Gunthorpe <jgg@nvidia.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
if (ITSTART(node) <= last) { /* Cond1 */ \
if (start <= ITLAST(node)) /* Cond2 */ \
return node; /* node is leftmost match */ \
- if (node->ITRB.rb_right) { \
- node = rb_entry(node->ITRB.rb_right, \
- ITSTRUCT, ITRB); \
- if (start <= node->ITSUBTREE) \
- continue; \
- } \
+ node = rb_entry(node->ITRB.rb_right, ITSTRUCT, ITRB); \
+ continue; \
} \
return NULL; /* No match */ \
} \