If the value to be shifted has the sign bit set, the sign
bit would get copied into bits 32..63 of the temporary. Those
would then be right shifted into the final value giving an
incorrect final result.
This was observed with upcoming GCC improvements which eliminate
unnecessary extensions.
break;
case 0x0B: /* lsr */
{
- unsigned long dst, src;
+ uint32_t dst, src;
dst = gr[RD];
src = gr[RS];
/* We must not rely solely upon the native shift operations, since they
case 0x3E: case 0x3F: /* lsrc, lsri */
{
unsigned imm = IMM5;
- unsigned long tmp = gr[RD];
+ uint32_t tmp = gr[RD];
if (imm == 0)
{
NEW_C (tmp);
--- /dev/null
+# check that lsr works correctly
+# mach: mcore
+
+.include "testutils.inc"
+
+ start
+ # Construct -1
+ bmaski r2, 32
+
+ # Construct 24
+ movi r3, 24
+
+ # logical shift right by r3 (24)
+ lsr r2, r3
+
+ # Construct 255
+ bmaski r1, 8
+
+ # Compare them, they should be equal
+ cmpne r2,r1
+ jbt .L1
+ pass
+.L1:
+ fail
+
+
+
+
--- /dev/null
+# check that lsri works correctly
+# mach: mcore
+
+.include "testutils.inc"
+
+ start
+ # Construct -1
+ bmaski r2, 32
+
+ # logical shift right by 24
+ lsri r2, 24
+
+ # Construct 255
+ bmaski r1, 8
+
+ # Compare them, they should be equal
+ cmpne r2,r1
+ jbt .L1
+ pass
+.L1:
+ fail
+
+
+
+