echo -e is not POSIX. Depending on what /bin/sh is, we can get
incorrect output like:
$ -e -n [1] Basic trace file check
$ -e [PASS]
Fix that by using printf instead.
Acked-by: Steven Rostedt (VMware) <rostedt@goodmis.org>
Acked-by: Masami Hiramatsu <mhiramat@kernel.org>
Signed-off-by: Juerg Haefliger <juergh@canonical.com>
Signed-off-by: Shuah Khan <shuah@kernel.org>
}
prlog() { # messages
- echo -e "$@"
- [ "$LOG_FILE" ] && echo -e "$@" | strip_esc >> $LOG_FILE
+ newline="\n"
+ if [ "$1" = "-n" ] ; then
+ newline=
+ shift
+ fi
+ printf "$*$newline"
+ [ "$LOG_FILE" ] && printf "$*$newline" | strip_esc >> $LOG_FILE
}
catlog() { #file
cat $1