The first thing the `parse_tree()` function does is to return early if
the tree has already been parsed. Therefore we do not need to guard the
`parse_tree()` call behind a check of that flag.
As of time of writing, there are no other instances of this in Git's
code bases: whenever the `parsed` flag guards a `parse_tree()` call, it
guards more than just that call.
Suggested-by: Patrick Steinhardt <ps@pks.im>
Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
struct cache_tree_sub *sub;
struct tree *subtree = lookup_tree(r, &entry.oid);
- if (!subtree->object.parsed && parse_tree(subtree) < 0)
+ if (parse_tree(subtree) < 0)
exit(128);
sub = cache_tree_sub(it, entry.path);
sub->cache_tree = cache_tree();