Recognize __builtin_free as being equivalent to free when passed into
__attribute__((malloc ())), similar to how it is treated when it is
encountered as a call. This fixes spurious warnings in glibc where
xmalloc family of allocators as well as reallocarray, memalign,
etc. are declared to have __builtin_free as the free function.
gcc/analyzer/ChangeLog:
* sm-malloc.cc
(malloc_state_machine::get_or_create_deallocator): Recognize
__builtin_free.
gcc/testsuite/ChangeLog:
* gcc.dg/analyzer/attr-malloc-1.c (compatible_alloc,
compatible_alloc2): New extern allocator declarations.
(test_9, test_10): New tests.
/* Reuse "free". */
deallocator *d;
if (is_named_call_p (deallocator_fndecl, "free")
- || is_std_named_call_p (deallocator_fndecl, "free"))
+ || is_std_named_call_p (deallocator_fndecl, "free")
+ || is_named_call_p (deallocator_fndecl, "__builtin_free"))
d = &m_free.m_deallocator;
else
{
extern void use_foo (const struct foo *)
__attribute__((nonnull));
+extern struct foo *compatible_alloc (void)
+ __attribute__ ((malloc (__builtin_free)));
+
+extern struct foo *compatible_alloc2 (void)
+ __attribute__ ((malloc (free)));
+
void test_1 (void)
{
struct foo *p = foo_acquire ();
foo_release (p);
return p->m_int; /* { dg-warning "use after 'foo_release' of 'p'" } */
}
+
+/* Recognize that __builtin_free and free are the same thing. */
+void test_9 (void)
+{
+ struct foo *p = compatible_alloc ();
+ free (p);
+}
+
+void test_10 (void)
+{
+ struct foo *p = compatible_alloc2 ();
+ __builtin_free (p);
+}