libstdc++: Fix test that fails randomly [PR101866]

This test assumes that the same sequence of three values cannot occur,
which is incorect. It's unlikely, but not impossible.

Perform the check in a loop, so that in the unlikely event of an
identical sequence, we retry. If the library code is buggy it will keep
producing the same sequence and the test will time out. If the code is
working correctly then we will usually break out of the loop after one
iteration, or very rarely after two or three.

libstdc++-v3/ChangeLog:

	PR libstdc++/101866
	* testsuite/experimental/random/randint.cc: Loop and retry if
	reseed() produces the same sequence.

diff --git a/libstdc++-v3/testsuite/experimental/random/randint.cc b/libstdc++-v3/testsuite/experimental/random/randint.cc
index d6225eba1dfbd5ba7bd74c900b4fd986cc988756..e05151e5ea09cf8fc18c80b8557d8c75771a8eb4 100644 (file)
--- a/libstdc++-v3/testsuite/experimental/random/randint.cc
+++ b/libstdc++-v3/testsuite/experimental/random/randint.cc
@@ -34,7 +34,7 @@ test01()
   }
 
   std::experimental::reseed(99u);
-  const long n1[] = {
+  const int n1[] = {
     std::experimental::randint(0, 100),
     std::experimental::randint(0, 100),
     std::experimental::randint(0, 100),
@@ -42,7 +42,7 @@ test01()
     std::experimental::randint(0, 100)
   };
   std::experimental::reseed(99u);
-  const long n2[] = {
+  const int n2[] = {
     std::experimental::randint(0, 100),
     std::experimental::randint(0, 100),
     std::experimental::randint(0, 100),
@@ -52,13 +52,13 @@ test01()
   for (int i = 0; i < 5; ++i)
     VERIFY( n1[i] == n2[i] );
 
-  std::experimental::reseed();
-  const long n3[] = {
-    std::experimental::randint(0, 100),
-    std::experimental::randint(0, 100),
-    std::experimental::randint(0, 100)
-  };
-  VERIFY( !(n3[0] == n1[0] && n3[1] == n1[1] && n3[2] == n1[2]) );
+  do
+  {
+    std::experimental::reseed();
+  }
+  while (std::experimental::randint(0, 100) == n1[0]
+      && std::experimental::randint(0, 100) == n1[1]
+      && std::experimental::randint(0, 100) == n1[2]);
 }
 
 void