After the conversion to locking guards within the interrupt core code,
several builds with clang show the "Interrupts were enabled early"
WARN() in start_kernel() on boot.
In class_irqdesc_lock_constructor(), _t.flags is initialized via
__irq_get_desc_lock() within the _t initializer list. However, the C11
standard 6.7.9.23 states that the evaluation of the initialization list
expressions are indeterminately sequenced relative to one another,
meaning _t.flags could be initialized by __irq_get_desc_lock() then be
initialized to zero due to flags being absent from the initializer list.
To ensure _t.flags is consistently initialized, move the call to
__irq_get_desc_lock() and the assignment of its result to _t.lock out of
the designated initializer.
Fixes: 0f70a49f3fa3 ("genirq: Provide conditional lock guards")
Signed-off-by: Nathan Chancellor <nathan@kernel.org>
Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
Reviewed-by: Jiri Slaby <jirislaby@kernel.org>
Link: https://lore.kernel.org/all/20250513-irq-guards-fix-flags-init-v1-1-1dca3f5992d6@kernel.org
static inline class_irqdesc_lock_t class_irqdesc_lock_constructor(unsigned int irq, bool bus,
unsigned int check)
{
- class_irqdesc_lock_t _t = {
- .bus = bus,
- .lock = __irq_get_desc_lock(irq, &_t.flags, bus, check),
- };
+ class_irqdesc_lock_t _t = { .bus = bus, };
+
+ _t.lock = __irq_get_desc_lock(irq, &_t.flags, bus, check);
+
return _t;
}