# arrays referenced using @ subscript and positional parameters should behave
# the same way

foo=(0 0 0); [[ -z ${foo[@]#0} ]]; echo $?

recho "${foo[@]#0}"
bar=${foo[@]#0}
recho bar
recho $bar
recho -$bar-
recho "$bar"

qux="${foo[@]#0}"
recho qux
recho $qux
recho -$qux-
recho "$qux"

unset foo qux bar

set -- 0 0 0

recho "${@#0}"
bar=${@#0}
recho bar
recho $bar
recho -$bar-
recho "$bar"

qux="${@#0}"
recho qux
recho $qux
recho -$qux-
recho "$qux"