Teach GDB that wchar_t is a built-in type in C++ mode
GDB is currently not aware that wchar_t is a built-in type in C++
mode. This is usually not a problem because the debug info describes
the type, so when you have a program loaded, you don't notice this.
However, if you try expressions involving wchar_t before a program is
loaded, gdb errors out:
(gdb) p (wchar_t)-1
No symbol table is loaded. Use the "file" command.
(gdb) p L"hello"
No type named wchar_t.
(gdb) ptype L"hello"
No type named wchar_t.
This commit teaches gdb about the type. After:
(gdb) p (wchar_t)-1
$1 = -1 L'\xffffffff'
(gdb) p L"hello"
$2 = L"hello"
(gdb) ptype L"hello"
type = wchar_t [6]
Unlike char16_t/char32_t, unfortunately, the underlying type of
wchar_t is implementation dependent, both size and signness. So this
requires adding a couple new gdbarch hooks.
I grepped the GCC code base for WCHAR_TYPE and WCHAR_TYPE_SIZE, and it
seems to me that the majority of the ABIs have a 4-byte signed
wchar_t, so that's what I made the default for GDB too. And then I
looked for which ports have a 16-bit and/or unsigned wchar_t, and made
GDB follow suit.
gdb/ChangeLog:
2017-04-12 Pedro Alves <palves@redhat.com>