The result of st_mult() is the same no matter the order of its
arguments. It invokes the macro unsigned_mult_overflows(), which
divides the second parameter by the first one. Pass constants
first to allow that division to be done already at compile time.
Signed-off-by: Rene Scharfe <l.s.r@web.de> Reviewed-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>