mkosi: Always use the embedded default version when no release is specified

Let's not have the host system determine the image distribution release.
Instead, let's always default to the default release embedded within mkosi.
This gives more consistent results when building images for a single distro
regardless of the host distribution.

diff --git a/NEWS.md b/NEWS.md
index 247b99d788f0a0981754274b48aee05597e87c66..8a96f43831378ce91eff2e71af022d99713311bc 100644 (file)
--- a/NEWS.md
+++ b/NEWS.md
@@ -16,6 +16,9 @@
   behavior, you can install the kernel-install script manually via a skeleton tree. The original script can be found
   [here](https://github.com/systemd/mkosi/blob/3798eb0c2ebcdf7dac207a559a3cb5a65cdb77b0/mkosi/resources/dracut_unified_kernel_install.sh).
 - Added QemuKvm option to configure whether to use KVM or not when running `mkosi qemu`.
+- mkosi won't default to the same OS release as the host system anymore when the host system uses the same
+  distribution as the image that's being built. Instead, when no release is specified, mkosi will now always
+  default to the default version embedded in mkosi itself.
 
 ## v12
 

diff --git a/mkosi/__init__.py b/mkosi/__init__.py
index d620f113c5004933a16afb3ecec5186a51ef2ec6..e674af7365db7655ac8a942cab03582c736de309 100644 (file)
--- a/mkosi/__init__.py
+++ b/mkosi/__init__.py
@@ -5801,9 +5801,6 @@ def load_distribution(args: argparse.Namespace) -> argparse.Namespace:
         if args.distribution is None:
             args.distribution = d
 
-        if args.distribution == d and d != Distribution.clear and args.release is None:
-            args.release = r
-
     if args.distribution is None:
         die("Couldn't detect distribution.")