Change the minimum slice extension to 5 usec.
Since slice_test selftest reaches a staggering ~350 nsec extension:
Task: slice_test Mean: 350.266 ns
Latency (us) | Count
------------------------------
EXPIRED | 238
0 us | 143189
1 us | 167
2 us | 26
3 us | 11
4 us | 28
5 us | 31
6 us | 22
7 us | 23
8 us | 32
9 us | 16
10 us | 35
Lower the minimal (and default) value to 5 usecs -- which is still massive.
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Link: https://patch.msgid.link/20260121143208.073200729@infradead.org
interrupted and the interrupt results in a reschedule request in the
kernel, then the kernel can grant a time slice extension and return to
userspace instead of scheduling out. The length of the extension is
-determined by debugfs:rseq/slice_ext_nsec. The default value is 10 usec; which
+determined by debugfs:rseq/slice_ext_nsec. The default value is 5 usec; which
is the minimum value. It can be incremented to 50 usecs, however doing so
can/will affect the minimum scheduling latency.
void *cookie;
};
-static const unsigned int rseq_slice_ext_nsecs_min = 10 * NSEC_PER_USEC;
+static const unsigned int rseq_slice_ext_nsecs_min = 5 * NSEC_PER_USEC;
static const unsigned int rseq_slice_ext_nsecs_max = 50 * NSEC_PER_USEC;
unsigned int rseq_slice_ext_nsecs __read_mostly = rseq_slice_ext_nsecs_min;
static DEFINE_PER_CPU(struct slice_timer, slice_timer);