typedef int thread_id;
+/* The mutex functions used to do absolutely nothing, i.e. lock,
+ trylock and unlock would always just return 0. However, even
+ without any concurrently active threads, a mutex can be used
+ legitimately as an `in use' flag. To make the code that is
+ protected by a mutex async-signal safe, these macros would have to
+ be based on atomic test-and-set operations, for example. */
typedef int mutex_t;
#define MUTEX_INITIALIZER 0
#define mutex_init(m) (*(m) = 0)
-#define mutex_lock(m) (0)
-#define mutex_trylock(m) (0)
-#define mutex_unlock(m) (0)
+#define mutex_lock(m) ((*(m) = 1), 0)
+#define mutex_trylock(m) (*(m) ? 1 : ((*(m) = 1), 0))
+#define mutex_unlock(m) (*(m) = 0)
typedef void *tsd_key_t;
#define tsd_key_create(key, destr) do {} while(0)
-#define tsd_setspecific(key, data) do {} while(0)
-#define tsd_getspecific(key, vptr) (vptr = NULL)
+#define tsd_setspecific(key, data) ((key) = (data))
+#define tsd_getspecific(key, vptr) (vptr = (key))
#define thread_atfork(prepare, parent, child) do {} while(0)