recipetool: create: lower case name when determining from filename

As a matter of general convention we expect recipe names to be lower
case; in fact some of the packaging backends insist upon it. Since in
this part of the code we're auto-determining the name, we should convert
the name to lowercase if it's not already so that we're following
convention and avoiding any validation issues later on.

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

diff --git a/scripts/lib/recipetool/create.py b/scripts/lib/recipetool/create.py
index 873b7ddcc6beac2b408ed25f38df4ea36cff4a1d..f3428577b9d59583984fbaeabdbf8b11bec6ed20 100644 (file)
--- a/scripts/lib/recipetool/create.py
+++ b/scripts/lib/recipetool/create.py
@@ -90,9 +90,9 @@ def determine_from_filename(srcfile):
     """Determine name and version from a filename"""
     part = ''
     if '.tar.' in srcfile:
-        namepart = srcfile.split('.tar.')[0]
+        namepart = srcfile.split('.tar.')[0].lower()
     else:
-        namepart = os.path.splitext(srcfile)[0]
+        namepart = os.path.splitext(srcfile)[0].lower()
     splitval = namepart.rsplit('_', 1)
     if len(splitval) == 1:
         splitval = namepart.rsplit('-', 1)