Fix "void debug (const tree_node *ptr)"

Calling "debug (const tree_node *ptr)" does nothing.  Change it to
call debug_tree so that we can do this in gdb:

(gdb) whatis type
type = const_tree
(gdb) call debug (type)
 <real_type 0x7fffe982f2a0 float sizes-gimplified SF
    size <integer_cst 0x7fffe98204e0 type <integer_type 0x7fffe98280a8 bitsizetype> constant 32>
    unit-size <integer_cst 0x7fffe98204f8 type <integer_type 0x7fffe9828000 sizetype> constant 4>
    align:32 warn_if_not_align:0 symtab:0 alias-set -1 canonical-type 0x7fffe982f2a0 precision:32
    pointer_to_this <pointer_type 0x7fffe982f930>>
(gdb)

	PR debug/120902
	* print-tree.cc (debug with const tree_node *): Call debug_tree
	instead of debug.

Signed-off-by: H.J. Lu <hjl.tools@gmail.com>

diff --git a/gcc/print-tree.cc b/gcc/print-tree.cc
index 6ec96f0ba171ed0d50df4698dbb303e040aa3540..f84be762741c7752042f8573f58e9aec3559896f 100644 (file)
--- a/gcc/print-tree.cc
+++ b/gcc/print-tree.cc
@@ -1193,7 +1193,7 @@ DEBUG_FUNCTION void
 debug (const tree_node *ptr)
 {
   if (ptr)
-    debug (*ptr);
+    debug_tree (const_cast <tree> (ptr));
   else
     fprintf (stderr, "<nil>\n");
 }