There is only one job when running "make JOBS=1", it should
print "sequential build" rather than "parallel build".
Before:
$ cd tools/perf && make JOBS=1
BUILD: Doing 'make -j1' parallel build
After:
$ cd tools/perf && make JOBS=1
BUILD: Doing 'make -j1' sequential build
Signed-off-by: Tiezhu Yang <yangtiezhu@loongson.cn>
Tested-by: Arnaldo Carvalho de Melo <acme@redhat.com>
Cc: Ingo Molnar <mingo@redhat.com>
Cc: Namhyung Kim <namhyung@kernel.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Link: https://lore.kernel.org/lkml/20240730062301.23244-2-yangtiezhu@loongson.cn
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
override DEBUG = 0
endif
+ifeq ($(JOBS),1)
+ BUILD_TYPE := sequential
+else
+ BUILD_TYPE := parallel
+endif
+
define print_msg
- @printf ' BUILD: Doing '\''make \033[33m-j'$(JOBS)'\033[m'\'' parallel build\n'
+ @printf ' BUILD: Doing '\''make \033[33m-j'$(JOBS)'\033[m'\'' $(BUILD_TYPE) build\n'
endef
define make