\begin{equation*}
-x^2 + y^2 = 1 + d' x^2 y^2 \pmod{p}
\end{equation*}
-(For this we use the same $d' = -d = (121665/121666) \bmod p$).
+(For this we use $d' = -d$, with $d = (121665/121666) \bmod p$, where
+$d$ is the same as in the curve25519 equivalence described below).
Assuming -1 has a square root modulo $p$, a point $(x, y)$ lies on
this curve if and only if $(\sqrt{-1} x, p)$ lies of the non-twisted
Edwards curve. The point addition formulas for the twisted Edwards
In our notation $a = -1$, and the $d'$ above is $-d$.
+\subsection{Decompression}
+
+For EdDSA, points are represented by the $y$ coordinate and only the
+low bit, or ``sign'' bit, of the $x$ coordinate. Then $x^2$ can be
+computed as
+\begin{align*}
+ x^2 &= (1-y^2) (d y^2 - 1)^{-1} \\
+ &= 121666 (1-y^2) (121665 y^2 - 121666)^{-1}
+\end{align*}
+We then get $x$ from a square root, and we can use a trick of djb's to
+avoid the inversion.
+
\section{Curve25519}
Curve25519 is defined as the Montgomery curve