The problem is this:
int n = ffs (w);
w >>= n;
The intent is to shift away up to (and including) the first least
significant bit in w. But w is an unsigned int, so 32 bits. And the
least significant bit could be bit 32 (ffs counts from 1). Unfortunately
a right shift equal to (or larger than) the length in bits of the left
hand operand is undefined behaviour. We expect w to be zero afterwards.
Which would terminate the while loop in the function. But since it is
undefined behaviour anything can happen. In this case, what will actually
happen is that w is unchanged, causing an infinite loop...
gcc -fsanitize=undefined will catch and warn about this when w = 0x80000000
https://bugzilla.redhat.com/show_bug.cgi?id=
1259259
Signed-off-by: Mark Wielaard <mjw@redhat.com>
+2015-09-03 Mark Wielaard <mjw@redhat.com>
+
+ * readelf.c (handle_core_item): Handle right shift >= 32 bits.
+
2015-08-11 Mark Wielaard <mjw@redhat.com>
* elflint.c (check_sections): When gnuld and a NOBITS section falls
unsigned int w = negate ? ~*i : *i;
while (w != 0)
{
- int n = ffs (w);
- w >>= n;
+ /* Note that a right shift equal to (or greater than)
+ the number of bits of w is undefined behaviour. In
+ particular when the least significant bit is bit 32
+ (w = 0x8000000) then w >>= n is undefined. So
+ explicitly handle that case separately. */
+ unsigned int n = ffs (w);
+ if (n < sizeof (w) * 8)
+ w >>= n;
+ else
+ w = 0;
bit += n;
if (lastbit != 0 && lastbit + 1 == bit)