movx.stderr.exp movx.stdout.exp movx.vgtest \
pushpopseg.stderr.exp pushpopseg.stdout.exp pushpopseg.vgtest \
sbbmisc.stderr.exp sbbmisc.stdout.exp sbbmisc.vgtest \
+ shift_ndep.stderr.exp shift_ndep.stdout.exp shift_ndep.vgtest \
smc1.stderr.exp smc1.stdout.exp smc1.vgtest \
ssse3_misaligned.stderr.exp ssse3_misaligned.stdout.exp \
ssse3_misaligned.vgtest ssse3_misaligned.c \
movx \
pushpopseg \
sbbmisc \
+ shift_ndep \
smc1 \
x86locked \
yield \
--- /dev/null
+#include "tests/asm.h"
+#include <stdio.h>
+
+/* Test whether a shift by zero properly preserves the CC_NDEP thunk. */
+
+/* Check whether the carry flag is properly preserved by a variable
+ shift when the shift amount happens to be zero. */
+int shift_ndep( void )
+{
+ char shift_amt = 0;
+ int x = -2;
+ /* First we set the carry flag. Then we increment %x, which sets
+ CC_OP to X86G_CC_OP_INCL and stores the carry (1) in
+ CC_NDEP. Then we left shift %x by a variable amount that happens
+ to be zero, which should leave both %x and all the flags
+ unchanged. Then we add-with-carry 0 to %x, which (assuming the
+ carry is still set as it should be) increments %x again. Thus the
+ expected final value for x is -2 + 1 + 1 = 0.
+
+ If instead the shift clears CC_NDEP (as it would legally do if
+ the shift amount were non-zero), this will be interpeted as
+ clearing the carry bit, so the adc will be a no-op and the final
+ value of %x will instead be -1.
+ */
+ asm (
+ "stc" "\n\t"
+ "inc %[x]" "\n\t"
+ "shl %[shift_amt], %[x]" "\n\t"
+ "adc $0, %[x]" "\n\t"
+ : [x] "+r" (x) : [shift_amt] "c" (shift_amt));
+ return x;
+}
+
+int main ( void )
+{
+ int r = shift_ndep();
+ if (r == 0)
+ printf("Passed (%d).\n", r);
+ else
+ printf("Failed (%d).\n", r);
+ return 0;
+}