+2000-07-31 Bruno Haible <haible@clisp.cons.org>
+
+ * plural.y: Include config.h. Needed to define 'inline' away for C
+ compilers that don't support it.
+ (yylex): Don't use gcc specific case range syntax.
+ * loadmsgcat.y (INIT_GERMANIC_PLURAL): New macro, for old compilers.
+
2000-07-28 Bruno Haible <haible@clisp.cons.org>
Simplification: In all cases where $(gnulocaledir) is used, it is
cached by one of GCC's features. */
int _nl_msg_cat_cntr;
+#if defined __GNUC__ \
+ || (defined __STDC_VERSION__ && __STDC_VERSION__ >= 199901L)
+
/* These structs are the constant expression for the germanic plural
- form determination. */
+ form determination. It represents the expression "n != 1". */
static const struct expression plvar =
{
.operation = var,
}
};
+#define INIT_GERMANIC_PLURAL()
+
+#else
+
+/* For compilers without support for ISO C 99 struct/union initializers:
+ Initialization at run-time. */
+
+static struct expression plvar;
+static struct expression plone;
+static struct expression germanic_plural;
+
+static void
+init_germanic_plural ()
+{
+ if (plone.val.num == 0)
+ {
+ plvar.operation = var;
+
+ plone.operation = num;
+ plone.val.num = 1;
+
+ germanic_plural.operation = not_equal;
+ germanic_plural.val.args2.left = &plvar;
+ germanic_plural.val.args2.right = &plone;
+ }
+}
+
+#define INIT_GERMANIC_PLURAL() init_germanic_plural ()
+
+#endif
+
/* Load the message catalogs specified by FILENAME. If it is no valid
message catalog do nothing. */
for `one', the plural form otherwise. Yes, this is also what
English is using since English is a Germanic language. */
no_plural:
+ INIT_GERMANIC_PLURAL ();
domain->plural = &germanic_plural;
domain->nplurals = 2;
}
along with this program; if not, write to the Free Software Foundation,
Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. */
+#ifdef HAVE_CONFIG_H
+# include <config.h>
+#endif
+
#include <stdarg.h>
#include <stdlib.h>
#include "gettext.h"
result = *exp++;
switch (result)
{
- case '0' ... '9':
+ case '0': case '1': case '2': case '3': case '4':
+ case '5': case '6': case '7': case '8': case '9':
{
unsigned long int n = exp[-1] - '0';
while (exp[0] >= '0' && exp[0] <= '9')