As mentioned in the previous commit, in _pat_ref_new(), it was not
strictly needed to explicitly assign all struct members to 0 since
the struct was allocated with calloc() which does the zeroing for us.
However, it was verified that we already initialize all fields explictly,
thus there is no reason to keep using calloc() instead of malloc(). In
fact using malloc() is less expensive, so let's use that instead now.
{
struct pat_ref *ref;
- ref = calloc(1, sizeof(*ref));
+ ref = malloc(sizeof(*ref));
if (!ref)
return NULL;
- /* For now is assumed <ref> was allocated with calloc() thus we don't
- * have to explicitly set all members to 0.
- */
+ /* don't forget to explicitly initialize all pat_ref struct members */
if (display) {
ref->display = strdup(display);