From: Paul Eggleton Date: Wed, 6 Jan 2016 11:15:49 +0000 (+1300) Subject: recipetool: create: lower case name when determining from filename X-Git-Tag: lucaceresoli/bug-15201-perf-libtraceevent-missing~27794 X-Git-Url: http://git.ipfire.org/cgi-bin/gitweb.cgi?a=commitdiff_plain;h=64986decbc11afa0d1e11251f5f7adcba1860d19;p=thirdparty%2Fopenembedded%2Fopenembedded-core-contrib.git recipetool: create: lower case name when determining from filename As a matter of general convention we expect recipe names to be lower case; in fact some of the packaging backends insist upon it. Since in this part of the code we're auto-determining the name, we should convert the name to lowercase if it's not already so that we're following convention and avoiding any validation issues later on. Signed-off-by: Paul Eggleton Signed-off-by: Richard Purdie --- diff --git a/scripts/lib/recipetool/create.py b/scripts/lib/recipetool/create.py index 873b7ddcc6b..f3428577b9d 100644 --- a/scripts/lib/recipetool/create.py +++ b/scripts/lib/recipetool/create.py @@ -90,9 +90,9 @@ def determine_from_filename(srcfile): """Determine name and version from a filename""" part = '' if '.tar.' in srcfile: - namepart = srcfile.split('.tar.')[0] + namepart = srcfile.split('.tar.')[0].lower() else: - namepart = os.path.splitext(srcfile)[0] + namepart = os.path.splitext(srcfile)[0].lower() splitval = namepart.rsplit('_', 1) if len(splitval) == 1: splitval = namepart.rsplit('-', 1)