Problem: dict_add_dict() frees the passed dict on one failure path
(when dict_add() fails) but not on the other (when
dictitem_alloc() fails), so a caller cannot tell whether it
still owns the dict after a failure. Callers that unref the
dict on failure (e.g. in window.c) then double-free it when
dict_add() fails.
Solution: Make the failure contract consistent: on failure leave the
passed dict untouched and owned by the caller; only take a
reference on success.
related: #20668
Supported by AI.
Signed-off-by: Christian Brabandt <cb@256bit.org>
return FAIL;
item->di_tv.v_type = VAR_DICT;
item->di_tv.vval.v_dict = dict;
- ++dict->dv_refcount;
if (dict_add(d, item) == FAIL)
{
+ // Detach "dict" so dictitem_free() does not unref it: on failure
+ // ownership stays with the caller.
+ item->di_tv.vval.v_dict = NULL;
dictitem_free(item);
return FAIL;
}
+ ++dict->dv_refcount;
return OK;
}
static int included_patches[] =
{ /* Add new patch number below this line */
+/**/
+ 770,
/**/
769,
/**/