# one should be enough, we modify the dict only.
header = routing.copy()
header[CC_HEADER_REPLY] = routing[CC_HEADER_SEQ]
- header[CC_HEADER_FROM] = "msgq" # Dummy lname not assigned to clients
+ # Dummy lname not assigned to clients
+ header[CC_HEADER_FROM] = "msgq"
header[CC_HEADER_TO] = routing[CC_HEADER_FROM]
# We keep the seq as it is. We don't need to track the message
- # and we will not confuse the sender. The sender would use an unique
- # id for each message, so we won't return one twice to it.
+ # and we will not confuse the sender. The sender would use an
+ # unique id for each message, so we won't return one twice to it.
errmsg = self.preparemsg(header, payload)
# Send it back.
self.send_prepared_msg(sock, errmsg)