return prog->aux->func_idx != 0;
}
+const struct bpf_line_info *bpf_find_linfo(const struct bpf_prog *prog, u32 insn_off);
void bpf_get_linfo_file_line(struct btf *btf, const struct bpf_line_info *linfo,
const char **filep, const char **linep, int *nump);
int bpf_prog_get_file_line(struct bpf_prog *prog, unsigned long ip, const char **filep,
*nump = BPF_LINE_INFO_LINE_NUM(linfo->line_col);
}
+const struct bpf_line_info *bpf_find_linfo(const struct bpf_prog *prog, u32 insn_off)
+{
+ const struct bpf_line_info *linfo;
+ u32 nr_linfo;
+ int l, r, m;
+
+ nr_linfo = prog->aux->nr_linfo;
+ if (!nr_linfo || insn_off >= prog->len)
+ return NULL;
+
+ linfo = prog->aux->linfo;
+ /* Loop invariant: linfo[l].insn_off <= insns_off.
+ * linfo[0].insn_off == 0 which always satisfies above condition.
+ * Binary search is searching for rightmost linfo entry that satisfies
+ * the above invariant, giving us the desired record that covers given
+ * instruction offset.
+ */
+ l = 0;
+ r = nr_linfo - 1;
+ while (l < r) {
+ /* (r - l + 1) / 2 means we break a tie to the right, so if:
+ * l=1, r=2, linfo[l].insn_off <= insn_off, linfo[r].insn_off > insn_off,
+ * then m=2, we see that linfo[m].insn_off > insn_off, and so
+ * r becomes 1 and we exit the loop with correct l==1.
+ * If the tie was broken to the left, m=1 would end us up in
+ * an endless loop where l and m stay at 1 and r stays at 2.
+ */
+ m = l + (r - l + 1) / 2;
+ if (linfo[m].insn_off <= insn_off)
+ l = m;
+ else
+ r = m - 1;
+ }
+
+ return &linfo[l];
+}
+
int bpf_prog_get_file_line(struct bpf_prog *prog, unsigned long ip, const char **filep,
const char **linep, int *nump)
{
}
EXPORT_SYMBOL_GPL(bpf_log);
-static const struct bpf_line_info *
-find_linfo(const struct bpf_verifier_env *env, u32 insn_off)
-{
- const struct bpf_line_info *linfo;
- const struct bpf_prog *prog;
- u32 nr_linfo;
- int l, r, m;
-
- prog = env->prog;
- nr_linfo = prog->aux->nr_linfo;
-
- if (!nr_linfo || insn_off >= prog->len)
- return NULL;
-
- linfo = prog->aux->linfo;
- /* Loop invariant: linfo[l].insn_off <= insns_off.
- * linfo[0].insn_off == 0 which always satisfies above condition.
- * Binary search is searching for rightmost linfo entry that satisfies
- * the above invariant, giving us the desired record that covers given
- * instruction offset.
- */
- l = 0;
- r = nr_linfo - 1;
- while (l < r) {
- /* (r - l + 1) / 2 means we break a tie to the right, so if:
- * l=1, r=2, linfo[l].insn_off <= insn_off, linfo[r].insn_off > insn_off,
- * then m=2, we see that linfo[m].insn_off > insn_off, and so
- * r becomes 1 and we exit the loop with correct l==1.
- * If the tie was broken to the left, m=1 would end us up in
- * an endless loop where l and m stay at 1 and r stays at 2.
- */
- m = l + (r - l + 1) / 2;
- if (linfo[m].insn_off <= insn_off)
- l = m;
- else
- r = m - 1;
- }
-
- return &linfo[l];
-}
-
static const char *ltrim(const char *s)
{
while (isspace(*s))
return;
prev_linfo = env->prev_linfo;
- linfo = find_linfo(env, insn_off);
+ linfo = bpf_find_linfo(env->prog, insn_off);
if (!linfo || linfo == prev_linfo)
return;