libc-package: ensure glibc-locale package list is deterministic

If all locales are being generated then the list used is the keys from a
dictionary.  In Python 3.4 onwards the ordering of a dictionary changes for
every instance, so sort the key list.

(From OE-Core rev: 7f6d7f729df37747be0d2cd2503cddca0184fd1f)

Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

diff --git a/meta/classes/libc-package.bbclass b/meta/classes/libc-package.bbclass
index 70f479bb41c9a00c951a6ce8a69f379971cbf3da..4f321d4865f6df68d3e723eeac9e10b39a96a3cb 100644 (file)
--- a/meta/classes/libc-package.bbclass
+++ b/meta/classes/libc-package.bbclass
@@ -226,7 +226,7 @@ python package_do_split_gconvs () {
     # GLIBC_GENERATE_LOCALES var specifies which locales to be generated. empty or "all" means all locales
     to_generate = d.getVar('GLIBC_GENERATE_LOCALES', True)
     if not to_generate or to_generate == 'all':
-        to_generate = supported.keys()
+        to_generate = sorted(supported.keys())
     else:
         to_generate = to_generate.split()
         for locale in to_generate:
@@ -391,4 +391,3 @@ python package_do_split_gconvs () {
 python populate_packages_prepend () {
     bb.build.exec_func('package_do_split_gconvs', d)
 }
-