From the MCTP Base specification (DSP0236 v1.2.1), the first byte of
the MCTP header contains a 4 bit reserved field, and 4 bit version.
On our current receive path, we require those 4 reserved bits to be
zero, but the 9500-8i card is non-conformant, and may set these
reserved bits.
DSP0236 states that the reserved bits must be written as zero, and
ignored when read. While the device might not conform to the former,
we should accept these message to conform to the latter.
Relax our check on the MCTP version byte to allow non-zero bits in the
reserved field.
Fixes: 889b7da23abf ("mctp: Add initial routing framework")
Signed-off-by: Yuan Zhaoming <yuanzm2@lenovo.com>
Cc: stable@vger.kernel.org
Acked-by: Jeremy Kerr <jk@codeconstruct.com.au>
Link: https://patch.msgid.link/20260417141340.5306-1-yuanzhaoming901030@126.com
Signed-off-by: Jakub Kicinski <kuba@kernel.org>
#define MCTP_VER_MIN 1
#define MCTP_VER_MAX 1
+/* Definitions for ver field */
+#define MCTP_HDR_VER_MASK GENMASK(3, 0)
+
/* Definitions for flags_seq_tag field */
#define MCTP_HDR_FLAG_SOM BIT(7)
#define MCTP_HDR_FLAG_EOM BIT(6)
unsigned long f;
u8 tag, flags;
int rc;
+ u8 ver;
msk = NULL;
rc = -EINVAL;
netid = mctp_cb(skb)->net;
skb_pull(skb, sizeof(struct mctp_hdr));
- if (mh->ver != 1)
+ ver = mh->ver & MCTP_HDR_VER_MASK;
+ if (ver < MCTP_VER_MIN || ver > MCTP_VER_MAX)
goto out;
flags = mh->flags_seq_tag & (MCTP_HDR_FLAG_SOM | MCTP_HDR_FLAG_EOM);
struct mctp_dst dst;
struct mctp_hdr *mh;
int rc;
+ u8 ver;
rcu_read_lock();
mdev = __mctp_dev_get(dev);
/* We have enough for a header; decode and route */
mh = mctp_hdr(skb);
- if (mh->ver < MCTP_VER_MIN || mh->ver > MCTP_VER_MAX)
+ ver = mh->ver & MCTP_HDR_VER_MASK;
+ if (ver < MCTP_VER_MIN || ver > MCTP_VER_MAX)
goto err_drop;
/* source must be valid unicast or null; drop reserved ranges and