remoteproc: snprintf() can return more than was printed

snprintf() returns the number of characters which would have been
printed if there were enough space.  For example, on the first print if
we fill up the 28 character string then it would return a number more
than 30.  Use scnprintf() instead because that returns the actual number
of characters printed.

Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com>
Signed-off-by: Ohad Ben-Cohen <ohad@wizery.com>

diff --git a/drivers/remoteproc/remoteproc_debugfs.c b/drivers/remoteproc/remoteproc_debugfs.c
index 10a38258e31dd07e1bc3a3ce3b273d8a5b4e6ed2..ea90a5643db3b153403df22245b1d70dc9ebbf40 100644 (file)
--- a/drivers/remoteproc/remoteproc_debugfs.c
+++ b/drivers/remoteproc/remoteproc_debugfs.c
@@ -82,7 +82,7 @@ static ssize_t rproc_state_read(struct file *filp, char __user *userbuf,
 
        state = rproc->state > RPROC_LAST ? RPROC_LAST : rproc->state;
 
-       i = snprintf(buf, 30, "%.28s (%d)\n", rproc_state_string[state],
+       i = scnprintf(buf, 30, "%.28s (%d)\n", rproc_state_string[state],
                                                        rproc->state);
 
        return simple_read_from_buffer(userbuf, count, ppos, buf, i);
@@ -103,7 +103,7 @@ static ssize_t rproc_name_read(struct file *filp, char __user *userbuf,
        char buf[100];
        int i;
 
-       i = snprintf(buf, sizeof(buf), "%.98s\n", rproc->name);
+       i = scnprintf(buf, sizeof(buf), "%.98s\n", rproc->name);
 
        return simple_read_from_buffer(userbuf, count, ppos, buf, i);
 }