target/i386: fix x86_64 pushw op

For x86_64 a 16 bit push op (pushw) of a memory address would generate
a 64 bit store on the stack instead of a 16 bit store.

For example:
        pushw (%rax)

behaves like
        pushq (%rax)

which is incorrect.

This patch fixes that.

Signed-off-by: Thomas Ogrisegg <tom-bugs-qemu@fnord.at>
Link: https://lore.kernel.org/r/20250715210307.GA1115@x1.fnord.at
Cc: qemu-stable@nongnu.org
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
(cherry picked from commit 5a2faa0a0a2cbdad4a108a0e122b0e51b9bc94fd)
Signed-off-by: Michael Tokarev <mjt@tls.msk.ru>

diff --git a/target/i386/tcg/decode-new.c.inc b/target/i386/tcg/decode-new.c.inc
index 51038657f0f99d508164e6d6abb321f7af71981b..a50f57dbaab315f53566bfcf483e86b887c87f16 100644 (file)
--- a/target/i386/tcg/decode-new.c.inc
+++ b/target/i386/tcg/decode-new.c.inc
@@ -1541,7 +1541,7 @@ static void decode_group4_5(DisasContext *s, CPUX86State *env, X86OpEntry *entry
         [0x0b] = X86_OP_ENTRYr(CALLF_m, M,p),
         [0x0c] = X86_OP_ENTRYr(JMP_m,   E,f64,                         zextT0),
         [0x0d] = X86_OP_ENTRYr(JMPF_m,  M,p),
-        [0x0e] = X86_OP_ENTRYr(PUSH,    E,f64),
+        [0x0e] = X86_OP_ENTRYr(PUSH,    E,d64),
     };
 
     int w = (*b & 1);