.. method:: most_common([n])
Return a list of the *n* most common elements and their counts from the
- most common to the least. If *n* is omitted or ``None`
- :func:`most_common` returns *all* elements in the count
- with equal counts are ordered arbitrarily:
+ most common to the least. If *n* is omitted or ``None``,
+ :func:`most_common` returns *all* elements in the counter.
+ Elements with equal counts are ordered arbitrarily:
>>> Counter('abracadabra').most_common(3)
[('a', 5), ('r', 2), ('b', 2)]