From: Raymond Hettinger Date: Thu, 10 Oct 2013 05:42:46 +0000 (-0700) Subject: Issue #19005: Fix documentation for PyIter_Next(). X-Git-Tag: v3.4.0a4~193^2 X-Git-Url: http://git.ipfire.org/gitweb.cgi?a=commitdiff_plain;h=8ee7708c7f7906f794a4f97ea2f9347e605ee245;p=thirdparty%2FPython%2Fcpython.git Issue #19005: Fix documentation for PyIter_Next(). --- diff --git a/Doc/c-api/iter.rst b/Doc/c-api/iter.rst index 3f0f554dadf9..2ba444d1de6d 100644 --- a/Doc/c-api/iter.rst +++ b/Doc/c-api/iter.rst @@ -5,7 +5,7 @@ Iterator Protocol ================= -There are only a couple of functions specifically for working with iterators. +There are two functions specifically for working with iterators. .. c:function:: int PyIter_Check(PyObject *o) @@ -14,11 +14,10 @@ There are only a couple of functions specifically for working with iterators. .. c:function:: PyObject* PyIter_Next(PyObject *o) - Return the next value from the iteration *o*. If the object is an iterator, - this retrieves the next value from the iteration, and returns *NULL* with no - exception set if there are no remaining items. If the object is not an - iterator, :exc:`TypeError` is raised, or if there is an error in retrieving the - item, returns *NULL* and passes along the exception. + Return the next value from the iteration *o*. The object must be an iterator + (it is up to the caller to check this). If there are no remaining values, + returns *NULL* with no exception set. If an error occurs while retrieving + the item, returns *NULL* and passes along the exception. To write a loop which iterates over an iterator, the C code should look something like this::