From: Victor Stinner <vstinner@python.org>
Date: Tue, 12 May 2020 01:07:40 +0000 (+0200)
Subject: bpo-40602: _Py_hashtable_new() uses PyMem_Malloc() (GH-20046)
X-Git-Tag: v3.9.0b1~111
X-Git-Url: http://git.ipfire.org/gitweb.cgi?a=commitdiff_plain;h=d0919f0d6bb757b6bcfd7b2e15656d318c9d5cd9;p=thirdparty%2FPython%2Fcpython.git

bpo-40602: _Py_hashtable_new() uses PyMem_Malloc() (GH-20046)

_Py_hashtable_new() now uses PyMem_Malloc/PyMem_Free allocator by
default, rather than PyMem_RawMalloc/PyMem_RawFree.

PyMem_Malloc is faster than PyMem_RawMalloc for memory blocks smaller
than or equal to 512 bytes.
---

diff --git a/Python/hashtable.c b/Python/hashtable.c
index 22b84590105f..e9f02d8650e4 100644
--- a/Python/hashtable.c
+++ b/Python/hashtable.c
@@ -149,11 +149,12 @@ _Py_hashtable_new_full(size_t key_size, size_t data_size,
     _Py_hashtable_allocator_t alloc;
 
     if (allocator == NULL) {
-        alloc.malloc = PyMem_RawMalloc;
-        alloc.free = PyMem_RawFree;
+        alloc.malloc = PyMem_Malloc;
+        alloc.free = PyMem_Free;
     }
-    else
+    else {
         alloc = *allocator;
+    }
 
     ht = (_Py_hashtable_t *)alloc.malloc(sizeof(_Py_hashtable_t));
     if (ht == NULL)