From: Miss Islington (bot) <31488909+miss-islington@users.noreply.github.com> Date: Tue, 29 Sep 2020 05:11:06 +0000 (-0700) Subject: bpo-41774: Add programming FAQ entry (GH-22402) X-Git-Tag: v3.8.7rc1~147 X-Git-Url: http://git.ipfire.org/gitweb.cgi?a=commitdiff_plain;h=d50a0700265536a20bcce3fb108c954746d97625;p=thirdparty%2FPython%2Fcpython.git bpo-41774: Add programming FAQ entry (GH-22402) In the "Sequences (Tuples/Lists)" section, add "How do you remove multiple items from a list". (cherry picked from commit 5b0181d1f6474c2cb9b80bdaf3bc56a78bf5fbe7) Co-authored-by: Terry Jan Reedy --- diff --git a/Doc/faq/programming.rst b/Doc/faq/programming.rst index 70e9190e5a52..1af04483eb32 100644 --- a/Doc/faq/programming.rst +++ b/Doc/faq/programming.rst @@ -1163,6 +1163,21 @@ This converts the list into a set, thereby removing duplicates, and then back into a list. +How do you remove multiple items from a list +-------------------------------------------- + +As with removing duplicates, explicitly iterating in reverse with a +delete condition is one possibility. However, it is easier and faster +to use slice replacement with an implicit or explicit forward iteration. +Here are three variations.:: + + mylist[:] = filter(keep_function, mylist) + mylist[:] = (x for x in mylist if keep_condition) + mylist[:] = [x for x in mylist if keep_condition] + +If space is not an issue, the list comprehension may be fastest. + + How do you make an array in Python? ----------------------------------- diff --git a/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst b/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst new file mode 100644 index 000000000000..af8e02437cb2 --- /dev/null +++ b/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst @@ -0,0 +1,2 @@ +In Programming FAQ "Sequences (Tuples/Lists)" section, add "How do you +remove multiple items from a list".