The recent fix in commit
1a5a33396d ("BUG/MEDIUM: jwe: substitute random
CEK on RSA1_5 decryption failure per RFC 7516 #11.5") writes 8 bytes at
once but stops at the last one, so it can overflow the sample by 7 bytes.
This is totally harmless since the max size is 64 bytes, but better stop
at the boundary. A final loop completes one byte at a time by construction
so that we can adapt to any value of MAX_DECRYPTED_CEK_LEN, but the compiler
will not emit it since we stop at 64.
No backport is needed, it's only for 3.4.
int i;
unsigned char *p = (unsigned char *)b_orig(decrypted_cek);
- for (i = 0; i < MAX_DECRYPTED_CEK_LEN; i++) {
+ /* fill 8 bytes at a time */
+ for (i = 0; i <= MAX_DECRYPTED_CEK_LEN - 8; i++) {
uint64_t r = ha_random64();
memcpy(p, &r, 8);
- p+=8;
+ p += 8;
}
+ /* complete if not multiple of 8 (normally not the case) */
+ for (; i < MAX_DECRYPTED_CEK_LEN; i++)
+ *(p++) = ha_random64();
+
outl = MAX_DECRYPTED_CEK_LEN;
} else
goto end;