]> git.ipfire.org Git - thirdparty/gcc.git/blame - gcc/tree-ssa-ifcombine.c
2007-06-12 Richard Guenther <rguenther@suse.de>
[thirdparty/gcc.git] / gcc / tree-ssa-ifcombine.c
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8530c7be 1/* Combining of if-expressions on trees.
2 Copyright (C) 2007 Free Software Foundation, Inc.
3 Contributed by Richard Guenther <rguenther@suse.de>
4
5This file is part of GCC.
6
7GCC is free software; you can redistribute it and/or modify
8it under the terms of the GNU General Public License as published by
9the Free Software Foundation; either version 2, or (at your option)
10any later version.
11
12GCC is distributed in the hope that it will be useful,
13but WITHOUT ANY WARRANTY; without even the implied warranty of
14MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
15GNU General Public License for more details.
16
17You should have received a copy of the GNU General Public License
18along with GCC; see the file COPYING. If not, write to
19the Free Software Foundation, 51 Franklin Street, Fifth Floor,
20Boston, MA 02110-1301, USA. */
21
22#include "config.h"
23#include "system.h"
24#include "coretypes.h"
25#include "tm.h"
26#include "tree.h"
27#include "basic-block.h"
28#include "timevar.h"
29#include "diagnostic.h"
30#include "tree-flow.h"
31#include "tree-pass.h"
32#include "tree-dump.h"
33
34/* This pass combines COND_EXPRs to simplify control flow. It
35 currently recognizes bit tests and comparisons in chains that
36 represent logical and or logical or of two COND_EXPRs.
37
38 It does so by walking basic blocks in a approximate reverse
39 post-dominator order and trying to match CFG patterns that
40 represent logical and or logical or of two COND_EXPRs.
41 Transformations are done if the COND_EXPR conditions match
42 either
43
44 1. two single bit tests X & (1 << Yn) (for logical and)
45
46 2. two bit tests X & Yn (for logical or)
47
48 3. two comparisons X OPn Y (for logical or)
49
50 To simplify this pass, removing basic blocks and dead code
51 is left to CFG cleanup and DCE. */
52
53
54/* Recognize a if-then-else CFG pattern starting to match with the
55 COND_BB basic-block containing the COND_EXPR. The recognized
56 then end else blocks are stored to *THEN_BB and *ELSE_BB. If
57 *THEN_BB and/or *ELSE_BB are already set, they are required to
58 match the then and else basic-blocks to make the pattern match.
59 Returns true if the pattern matched, false otherwise. */
60
61static bool
62recognize_if_then_else (basic_block cond_bb,
63 basic_block *then_bb, basic_block *else_bb)
64{
65 edge t, e;
66
67 if (EDGE_COUNT (cond_bb->succs) != 2)
68 return false;
69
70 /* Find the then/else edges. */
71 t = EDGE_SUCC (cond_bb, 0);
72 e = EDGE_SUCC (cond_bb, 1);
73 if (!(t->flags & EDGE_TRUE_VALUE))
74 {
75 edge tmp = t;
76 t = e;
77 e = tmp;
78 }
79 if (!(t->flags & EDGE_TRUE_VALUE)
80 || !(e->flags & EDGE_FALSE_VALUE))
81 return false;
82
83 /* Check if the edge destinations point to the required block. */
84 if (*then_bb
85 && t->dest != *then_bb)
86 return false;
87 if (*else_bb
88 && e->dest != *else_bb)
89 return false;
90
91 if (!*then_bb)
92 *then_bb = t->dest;
93 if (!*else_bb)
94 *else_bb = e->dest;
95
96 return true;
97}
98
99/* Verify if the basic block BB does not have side-effects. Return
100 true in this case, else false. */
101
102static bool
103bb_no_side_effects_p (basic_block bb)
104{
105 block_stmt_iterator bsi;
106
107 for (bsi = bsi_start (bb); !bsi_end_p (bsi); bsi_next (&bsi))
108 {
109 tree stmt = bsi_stmt (bsi);
110 stmt_ann_t ann = stmt_ann (stmt);
111
112 if (ann->has_volatile_ops
113 || !ZERO_SSA_OPERANDS (stmt, SSA_OP_ALL_VIRTUALS))
114 return false;
115 }
116
117 return true;
118}
119
120/* Verify if all PHI node arguments in DEST for edges from BB1 or
121 BB2 to DEST are the same. This makes the CFG merge point
122 free from side-effects. Return true in this case, else false. */
123
124static bool
125same_phi_args_p (basic_block bb1, basic_block bb2, basic_block dest)
126{
127 edge e1 = find_edge (bb1, dest);
128 edge e2 = find_edge (bb2, dest);
129 tree phi;
130
131 for (phi = phi_nodes (dest); phi; phi = PHI_CHAIN (phi))
132 if (!operand_equal_p (PHI_ARG_DEF_FROM_EDGE (phi, e1),
133 PHI_ARG_DEF_FROM_EDGE (phi, e2), 0))
134 return false;
135
136 return true;
137}
138
139/* Recognize a single bit test pattern in COND_EXPR and its defining
140 statements. Store the name being tested in *NAME and the bit
141 in *BIT. The COND_EXPR computes *NAME & (1 << *BIT).
142 Returns true if the pattern matched, false otherwise. */
143
144static bool
145recognize_single_bit_test (tree cond_expr, tree *name, tree *bit)
146{
147 tree t;
148
149 /* Get at the definition of the result of the bit test. */
150 t = TREE_OPERAND (cond_expr, 0);
151 if (TREE_CODE (t) == NE_EXPR
152 && integer_zerop (TREE_OPERAND (t, 1)))
153 t = TREE_OPERAND (t, 0);
154 if (TREE_CODE (t) != SSA_NAME)
155 return false;
156 t = SSA_NAME_DEF_STMT (t);
157 if (TREE_CODE (t) != GIMPLE_MODIFY_STMT)
158 return false;
159 t = GIMPLE_STMT_OPERAND (t, 1);
160
161 /* Look at which bit is tested. One form to recognize is
162 D.1985_5 = state_3(D) >> control1_4(D);
163 D.1986_6 = (int) D.1985_5;
164 D.1987_7 = op0 & 1;
165 if (D.1987_7 != 0) */
166 if (TREE_CODE (t) == BIT_AND_EXPR
167 && integer_onep (TREE_OPERAND (t, 1))
168 && TREE_CODE (TREE_OPERAND (t, 0)) == SSA_NAME)
169 {
170 t = TREE_OPERAND (t, 0);
171 do {
172 t = SSA_NAME_DEF_STMT (t);
173 if (TREE_CODE (t) != GIMPLE_MODIFY_STMT)
174 return false;
175 t = GIMPLE_STMT_OPERAND (t, 1);
176 if (TREE_CODE (t) == NOP_EXPR
177 || TREE_CODE (t) == CONVERT_EXPR)
178 t = TREE_OPERAND (t, 0);
179 } while (TREE_CODE (t) == SSA_NAME);
180
181 if (TREE_CODE (t) == RSHIFT_EXPR)
182 {
183 /* op0 & (1 << op1) */
184 *bit = TREE_OPERAND (t, 1);
185 *name = TREE_OPERAND (t, 0);
186 }
187 else
188 {
189 /* t & 1 */
190 *bit = integer_one_node;
191 *name = t;
192 }
193
194 return true;
195 }
196
197 /* Another form is
198 D.1987_7 = op0 & (1 << CST)
199 if (D.1987_7 != 0) */
200 if (TREE_CODE (t) == BIT_AND_EXPR
201 && TREE_CODE (TREE_OPERAND (t, 0)) == SSA_NAME
202 && integer_pow2p (TREE_OPERAND (t, 1)))
203 {
204 *name = TREE_OPERAND (t, 0);
205 *bit = build_int_cst (integer_type_node,
206 tree_log2 (TREE_OPERAND (t, 1)));
207 return true;
208 }
209
210 /* Another form is
211 D.1986_6 = 1 << control1_4(D)
212 D.1987_7 = op0 & D.1986_6
213 if (D.1987_7 != 0) */
214 if (TREE_CODE (t) == BIT_AND_EXPR
215 && TREE_CODE (TREE_OPERAND (t, 0)) == SSA_NAME
216 && TREE_CODE (TREE_OPERAND (t, 1)) == SSA_NAME)
217 {
218 tree tmp;
219
220 /* Both arguments of the BIT_AND_EXPR can be the single-bit
221 specifying expression. */
222 tmp = SSA_NAME_DEF_STMT (TREE_OPERAND (t, 0));
223 if (TREE_CODE (tmp) == GIMPLE_MODIFY_STMT
224 && TREE_CODE (GIMPLE_STMT_OPERAND (tmp, 1)) == LSHIFT_EXPR
225 && integer_onep (TREE_OPERAND (GIMPLE_STMT_OPERAND (tmp, 1), 0)))
226 {
227 *name = TREE_OPERAND (t, 1);
228 *bit = TREE_OPERAND (GIMPLE_STMT_OPERAND (tmp, 1), 1);
229 return true;
230 }
231
232 tmp = SSA_NAME_DEF_STMT (TREE_OPERAND (t, 1));
233 if (TREE_CODE (tmp) == GIMPLE_MODIFY_STMT
234 && TREE_CODE (GIMPLE_STMT_OPERAND (tmp, 1)) == LSHIFT_EXPR
235 && integer_onep (TREE_OPERAND (GIMPLE_STMT_OPERAND (tmp, 1), 0)))
236 {
237 *name = TREE_OPERAND (t, 0);
238 *bit = TREE_OPERAND (GIMPLE_STMT_OPERAND (tmp, 1), 1);
239 return true;
240 }
241 }
242
243 return false;
244}
245
246/* Recognize a bit test pattern in COND_EXPR and its defining
247 statements. Store the name being tested in *NAME and the bits
248 in *BITS. The COND_EXPR computes *NAME & *BITS.
249 Returns true if the pattern matched, false otherwise. */
250
251static bool
252recognize_bits_test (tree cond_expr, tree *name, tree *bits)
253{
254 tree t;
255
256 /* Get at the definition of the result of the bit test. */
257 t = TREE_OPERAND (cond_expr, 0);
258 if (TREE_CODE (t) == NE_EXPR
259 && integer_zerop (TREE_OPERAND (t, 1)))
260 t = TREE_OPERAND (t, 0);
261 if (TREE_CODE (t) != SSA_NAME)
262 return false;
263 t = SSA_NAME_DEF_STMT (t);
264 if (TREE_CODE (t) != GIMPLE_MODIFY_STMT)
265 return false;
266 t = GIMPLE_STMT_OPERAND (t, 1);
267
268 if (TREE_CODE (t) != BIT_AND_EXPR)
269 return false;
270
271 *name = TREE_OPERAND (t, 0);
272 *bits = TREE_OPERAND (t, 1);
273
274 return true;
275}
276
277/* If-convert on a and pattern with a common else block. The inner
278 if is specified by its INNER_COND_BB, the outer by OUTER_COND_BB.
279 Returns true if the edges to the common else basic-block were merged. */
280
281static bool
282ifcombine_ifandif (basic_block inner_cond_bb, basic_block outer_cond_bb)
283{
284 block_stmt_iterator bsi;
285 tree inner_cond, outer_cond;
286 tree name1, name2, bit1, bit2;
287
288 inner_cond = last_stmt (inner_cond_bb);
289 if (!inner_cond
290 || TREE_CODE (inner_cond) != COND_EXPR)
291 return false;
292
293 outer_cond = last_stmt (outer_cond_bb);
294 if (!outer_cond
295 || TREE_CODE (outer_cond) != COND_EXPR)
296 return false;
297
298 /* See if we test a single bit of the same name in both tests. In
299 that case remove the outer test, merging both else edges,
300 and change the inner one to test for
301 name & (bit1 | bit2) == (bit1 | bit2). */
302 if (recognize_single_bit_test (inner_cond, &name1, &bit1)
303 && recognize_single_bit_test (outer_cond, &name2, &bit2)
304 && name1 == name2)
305 {
306 tree t, t2;
307
308 /* Do it. */
309 bsi = bsi_for_stmt (inner_cond);
310 t = fold_build2 (LSHIFT_EXPR, TREE_TYPE (name1),
311 integer_one_node, bit1);
312 t2 = fold_build2 (LSHIFT_EXPR, TREE_TYPE (name1),
313 integer_one_node, bit2);
314 t = fold_build2 (BIT_IOR_EXPR, TREE_TYPE (name1), t, t2);
315 t = force_gimple_operand_bsi (&bsi, t, true, NULL_TREE);
316 t2 = fold_build2 (BIT_AND_EXPR, TREE_TYPE (name1), name1, t);
317 t2 = force_gimple_operand_bsi (&bsi, t2, true, NULL_TREE);
318 COND_EXPR_COND (inner_cond) = fold_build2 (EQ_EXPR, boolean_type_node,
319 t2, t);
320 update_stmt (inner_cond);
321
322 /* Leave CFG optimization to cfg_cleanup. */
323 COND_EXPR_COND (outer_cond) = boolean_true_node;
324 update_stmt (outer_cond);
325
326 if (dump_file)
327 {
328 fprintf (dump_file, "optimizing double bit test to ");
329 print_generic_expr (dump_file, name1, 0);
330 fprintf (dump_file, " & T == T\nwith temporary T = (1 << ");
331 print_generic_expr (dump_file, bit1, 0);
332 fprintf (dump_file, ") | (1 << ");
333 print_generic_expr (dump_file, bit2, 0);
334 fprintf (dump_file, ")\n");
335 }
336
337 return true;
338 }
339
340 return false;
341}
342
343/* If-convert on a or pattern with a common then block. The inner
344 if is specified by its INNER_COND_BB, the outer by OUTER_COND_BB.
345 Returns true, if the edges leading to the common then basic-block
346 were merged. */
347
348static bool
349ifcombine_iforif (basic_block inner_cond_bb, basic_block outer_cond_bb)
350{
351 tree inner_cond, outer_cond;
352 tree name1, name2, bits1, bits2;
353
354 inner_cond = last_stmt (inner_cond_bb);
355 if (!inner_cond
356 || TREE_CODE (inner_cond) != COND_EXPR)
357 return false;
358
359 outer_cond = last_stmt (outer_cond_bb);
360 if (!outer_cond
361 || TREE_CODE (outer_cond) != COND_EXPR)
362 return false;
363
364 /* See if we have two bit tests of the same name in both tests.
365 In that case remove the outer test and change the inner one to
366 test for name & (bits1 | bits2) != 0. */
367 if (recognize_bits_test (inner_cond, &name1, &bits1)
368 && recognize_bits_test (outer_cond, &name2, &bits2))
369 {
370 block_stmt_iterator bsi;
371 tree t;
372
373 /* Find the common name which is bit-tested. */
374 if (name1 == name2)
375 ;
376 else if (bits1 == bits2)
377 {
378 t = name2;
379 name2 = bits2;
380 bits2 = t;
381 t = name1;
382 name1 = bits1;
383 bits1 = t;
384 }
385 else if (name1 == bits2)
386 {
387 t = name2;
388 name2 = bits2;
389 bits2 = t;
390 }
391 else if (bits1 == name2)
392 {
393 t = name1;
394 name1 = bits1;
395 bits1 = t;
396 }
397 else
398 return false;
399
400 /* Do it. */
401 bsi = bsi_for_stmt (inner_cond);
402 t = fold_build2 (BIT_IOR_EXPR, TREE_TYPE (name1), bits1, bits2);
403 t = force_gimple_operand_bsi (&bsi, t, true, NULL_TREE);
404 t = fold_build2 (BIT_AND_EXPR, TREE_TYPE (name1), name1, t);
405 t = force_gimple_operand_bsi (&bsi, t, true, NULL_TREE);
406 COND_EXPR_COND (inner_cond) = fold_build2 (NE_EXPR, boolean_type_node, t,
407 build_int_cst (TREE_TYPE (t), 0));
408 update_stmt (inner_cond);
409
410 /* Leave CFG optimization to cfg_cleanup. */
411 COND_EXPR_COND (outer_cond) = boolean_false_node;
412 update_stmt (outer_cond);
413
414 if (dump_file)
415 {
416 fprintf (dump_file, "optimizing bits or bits test to ");
417 print_generic_expr (dump_file, name1, 0);
418 fprintf (dump_file, " & T != 0\nwith temporary T = ");
419 print_generic_expr (dump_file, bits1, 0);
420 fprintf (dump_file, " | ");
421 print_generic_expr (dump_file, bits2, 0);
422 fprintf (dump_file, "\n");
423 }
424
425 return true;
426 }
427
428 /* See if we have two comparisons that we can merge into one.
429 This happens for C++ operator overloading where for example
430 GE_EXPR is implemented as GT_EXPR || EQ_EXPR. */
431 else if (COMPARISON_CLASS_P (COND_EXPR_COND (inner_cond))
432 && COMPARISON_CLASS_P (COND_EXPR_COND (outer_cond))
433 && operand_equal_p (TREE_OPERAND (COND_EXPR_COND (inner_cond), 0),
434 TREE_OPERAND (COND_EXPR_COND (outer_cond), 0), 0)
435 && operand_equal_p (TREE_OPERAND (COND_EXPR_COND (inner_cond), 1),
436 TREE_OPERAND (COND_EXPR_COND (outer_cond), 1), 0))
437 {
438 tree ccond1 = COND_EXPR_COND (inner_cond);
439 tree ccond2 = COND_EXPR_COND (outer_cond);
440 enum tree_code code1 = TREE_CODE (ccond1);
441 enum tree_code code2 = TREE_CODE (ccond2);
442 enum tree_code code;
443 tree t;
444
445#define CHK(a,b) ((code1 == a ## _EXPR && code2 == b ## _EXPR) \
446 || (code2 == a ## _EXPR && code1 == b ## _EXPR))
447 /* Merge the two condition codes if possible. */
448 if (code1 == code2)
449 code = code1;
450 else if (CHK (EQ, LT))
451 code = LE_EXPR;
452 else if (CHK (EQ, GT))
453 code = GE_EXPR;
454 else if (CHK (LT, LE))
455 code = LE_EXPR;
456 else if (CHK (GT, GE))
457 code = GE_EXPR;
458 else if (INTEGRAL_TYPE_P (TREE_TYPE (TREE_OPERAND (ccond1, 0)))
459 || flag_unsafe_math_optimizations)
460 {
461 if (CHK (LT, GT))
462 code = NE_EXPR;
463 else if (CHK (LT, NE))
464 code = NE_EXPR;
465 else if (CHK (GT, NE))
466 code = NE_EXPR;
467 else
468 return false;
469 }
470 /* We could check for combinations leading to trivial true/false. */
471 else
472 return false;
473#undef CHK
474
475 /* Do it. */
476 t = fold_build2 (code, boolean_type_node,
477 TREE_OPERAND (ccond2, 0), TREE_OPERAND (ccond2, 1));
478 COND_EXPR_COND (inner_cond) = t;
479 update_stmt (inner_cond);
480
481 /* Leave CFG optimization to cfg_cleanup. */
482 COND_EXPR_COND (outer_cond) = boolean_false_node;
483 update_stmt (outer_cond);
484
485 if (dump_file)
486 {
487 fprintf (dump_file, "optimizing two comparisons to ");
488 print_generic_expr (dump_file, t, 0);
489 fprintf (dump_file, "\n");
490 }
491
492 return true;
493 }
494
495 return false;
496}
497
498/* Recognize a CFG pattern and dispatch to the appropriate
499 if-conversion helper. We start with BB as the innermost
500 worker basic-block. Returns true if a transformation was done. */
501
502static bool
503tree_ssa_ifcombine_bb (basic_block inner_cond_bb)
504{
505 basic_block then_bb = NULL, else_bb = NULL;
506
507 if (!recognize_if_then_else (inner_cond_bb, &then_bb, &else_bb))
508 return false;
509
510 /* Recognize && and || of two conditions with a common
511 then/else block which entry edges we can merge. That is:
512 if (a || b)
513 ;
514 and
515 if (a && b)
516 ;
517 This requires a single predecessor of the inner cond_bb. */
518 if (single_pred_p (inner_cond_bb))
519 {
520 basic_block outer_cond_bb = single_pred (inner_cond_bb);
521
522 /* The && form is characterized by a common else_bb with
523 the two edges leading to it mergable. The latter is
524 guaranteed by matching PHI arguments in the else_bb and
525 the inner cond_bb having no side-effects. */
526 if (recognize_if_then_else (outer_cond_bb, &inner_cond_bb, &else_bb)
527 && same_phi_args_p (outer_cond_bb, inner_cond_bb, else_bb)
528 && bb_no_side_effects_p (inner_cond_bb))
529 {
530 /* We have
531 <outer_cond_bb>
532 if (q) goto inner_cond_bb; else goto else_bb;
533 <inner_cond_bb>
534 if (p) goto ...; else goto else_bb;
535 ...
536 <else_bb>
537 ...
538 */
539 return ifcombine_ifandif (inner_cond_bb, outer_cond_bb);
540 }
541
542 /* The || form is characterized by a common then_bb with the
543 two edges leading to it mergable. The latter is guaranteed
544 by matching PHI arguments in the then_bb and the inner cond_bb
545 having no side-effects. */
546 if (recognize_if_then_else (outer_cond_bb, &then_bb, &inner_cond_bb)
547 && same_phi_args_p (outer_cond_bb, inner_cond_bb, then_bb)
548 && bb_no_side_effects_p (inner_cond_bb))
549 {
550 /* We have
551 <outer_cond_bb>
552 if (q) goto then_bb; else goto inner_cond_bb;
553 <inner_cond_bb>
554 if (q) goto then_bb; else goto ...;
555 <then_bb>
556 ...
557 */
558 return ifcombine_iforif (inner_cond_bb, outer_cond_bb);
559 }
560 }
561
562 return false;
563}
564
565/* Main entry for the tree if-conversion pass. */
566
567static unsigned int
568tree_ssa_ifcombine (void)
569{
570 basic_block *bbs;
571 bool cfg_changed = false;
572 int i;
573
574 bbs = blocks_in_phiopt_order ();
575
576 for (i = 0; i < n_basic_blocks - NUM_FIXED_BLOCKS; ++i)
577 {
578 basic_block bb = bbs[i];
579 tree stmt = last_stmt (bb);
580
581 if (stmt
582 && TREE_CODE (stmt) == COND_EXPR)
583 cfg_changed |= tree_ssa_ifcombine_bb (bb);
584 }
585
586 free (bbs);
587
588 return cfg_changed ? TODO_cleanup_cfg : 0;
589}
590
591static bool
592gate_ifcombine (void)
593{
594 return 1;
595}
596
597struct tree_opt_pass pass_tree_ifcombine = {
598 "ifcombine", /* name */
599 gate_ifcombine, /* gate */
600 tree_ssa_ifcombine, /* execute */
601 NULL, /* sub */
602 NULL, /* next */
603 0, /* static_pass_number */
604 TV_TREE_IFCOMBINE, /* tv_id */
605 PROP_cfg | PROP_ssa, /* properties_required */
606 0, /* properties_provided */
607 0, /* properties_destroyed */
608 0, /* todo_flags_start */
609 TODO_dump_func
610 | TODO_ggc_collect
611 | TODO_update_ssa
612 | TODO_verify_ssa, /* todo_flags_finish */
613 0 /* letter */
614};