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1/* Array prefetching.
2 Copyright (C) 2005 Free Software Foundation, Inc.
3
4This file is part of GCC.
5
6GCC is free software; you can redistribute it and/or modify it
7under the terms of the GNU General Public License as published by the
8Free Software Foundation; either version 2, or (at your option) any
9later version.
10
11GCC is distributed in the hope that it will be useful, but WITHOUT
12ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
13FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
14for more details.
15
16You should have received a copy of the GNU General Public License
17along with GCC; see the file COPYING. If not, write to the Free
18Software Foundation, 59 Temple Place - Suite 330, Boston, MA
1902111-1307, USA. */
20
21#include "config.h"
22#include "system.h"
23#include "coretypes.h"
24#include "tm.h"
25#include "tree.h"
26#include "rtl.h"
27#include "tm_p.h"
28#include "hard-reg-set.h"
29#include "basic-block.h"
30#include "output.h"
31#include "diagnostic.h"
32#include "tree-flow.h"
33#include "tree-dump.h"
34#include "timevar.h"
35#include "cfgloop.h"
36#include "varray.h"
37#include "expr.h"
38#include "tree-pass.h"
39#include "ggc.h"
40#include "insn-config.h"
41#include "recog.h"
42#include "hashtab.h"
43#include "tree-chrec.h"
44#include "tree-scalar-evolution.h"
45#include "toplev.h"
46#include "params.h"
47#include "langhooks.h"
48
49/* This pass inserts prefetch instructions to optimize cache usage during
50 accesses to arrays in loops. It processes loops sequentially and:
51
52 1) Gathers all memory references in the single loop.
53 2) For each of the references it decides when it is profitable to prefetch
54 it. To do it, we evaluate the reuse among the accesses, and determines
55 two values: PREFETCH_BEFORE (meaning that it only makes sense to do
56 prefetching in the first PREFETCH_BEFORE iterations of the loop) and
57 PREFETCH_MOD (meaning that it only makes sense to prefetch in the
58 iterations of the loop that are zero modulo PREFETCH_MOD). For example
59 (assuming cache line size is 64 bytes, char has size 1 byte and there
60 is no hardware sequential prefetch):
61
62 char *a;
63 for (i = 0; i < max; i++)
64 {
65 a[255] = ...; (0)
66 a[i] = ...; (1)
67 a[i + 64] = ...; (2)
68 a[16*i] = ...; (3)
69 a[187*i] = ...; (4)
70 a[187*i + 50] = ...; (5)
71 }
72
73 (0) obviously has PREFETCH_BEFORE 1
74 (1) has PREFETCH_BEFORE 64, since (2) accesses the same memory
75 location 64 iterations before it, and PREFETCH_MOD 64 (since
76 it hits the same cache line otherwise).
77 (2) has PREFETCH_MOD 64
78 (3) has PREFETCH_MOD 4
79 (4) has PREFETCH_MOD 1. We do not set PREFETCH_BEFORE here, since
80 the cache line accessed by (4) is the same with probability only
81 7/32.
82 (5) has PREFETCH_MOD 1 as well.
83
84 3) We determine how much ahead we need to prefetch. The number of
85 iterations needed is time to fetch / time spent in one iteration of
86 the loop. The problem is that we do not know either of these values,
87 so we just make a heuristic guess based on a magic (possibly)
88 target-specific constant and size of the loop.
89
90 4) Determine which of the references we prefetch. We take into account
91 that there is a maximum number of simultaneous prefetches (provided
92 by machine description). We prefetch as many prefetches as possible
93 while still within this bound (starting with those with lowest
94 prefetch_mod, since they are responsible for most of the cache
95 misses).
96
97 5) We unroll and peel loops so that we are able to satisfy PREFETCH_MOD
98 and PREFETCH_BEFORE requirements (within some bounds), and to avoid
99 prefetching nonaccessed memory.
100 TODO -- actually implement peeling.
101
102 6) We actually emit the prefetch instructions. ??? Perhaps emit the
103 prefetch instructions with guards in cases where 5) was not sufficient
104 to satisfy the constraints?
105
106 Some other TODO:
107 -- write and use more general reuse analysis (that could be also used
108 in other cache aimed loop optimizations)
109 -- make it behave sanely together with the prefetches given by user
110 (now we just ignore them; at the very least we should avoid
111 optimizing loops in that user put his own prefetches)
112 -- we assume cache line size alignment of arrays; this could be
113 improved. */
114
115/* Magic constants follow. These should be replaced by machine specific
116 numbers. */
117
c0220ea4 118/* A number that should roughly correspond to the number of instructions
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119 executed before the prefetch is completed. */
120
121#ifndef PREFETCH_LATENCY
122#define PREFETCH_LATENCY 200
123#endif
124
125/* Number of prefetches that can run at the same time. */
126
127#ifndef SIMULTANEOUS_PREFETCHES
128#define SIMULTANEOUS_PREFETCHES 3
129#endif
130
131/* True if write can be prefetched by a read prefetch. */
132
133#ifndef WRITE_CAN_USE_READ_PREFETCH
134#define WRITE_CAN_USE_READ_PREFETCH 1
135#endif
136
137/* True if read can be prefetched by a write prefetch. */
138
139#ifndef READ_CAN_USE_WRITE_PREFETCH
140#define READ_CAN_USE_WRITE_PREFETCH 0
141#endif
142
143/* Cache line size. Assumed to be a power of two. */
144
145#ifndef PREFETCH_BLOCK
146#define PREFETCH_BLOCK 32
147#endif
148
149/* Do we have a forward hardware sequential prefetching? */
150
151#ifndef HAVE_FORWARD_PREFETCH
152#define HAVE_FORWARD_PREFETCH 0
153#endif
154
155/* Do we have a backward hardware sequential prefetching? */
156
157#ifndef HAVE_BACKWARD_PREFETCH
158#define HAVE_BACKWARD_PREFETCH 0
159#endif
160
161/* In some cases we are only able to determine that there is a certain
162 probability that the two accesses hit the same cache line. In this
163 case, we issue the prefetches for both of them if this probability
164 is less then (1000 - ACCEPTABLE_MISS_RATE) promile. */
165
166#ifndef ACCEPTABLE_MISS_RATE
167#define ACCEPTABLE_MISS_RATE 50
168#endif
169
170#ifndef HAVE_prefetch
171#define HAVE_prefetch 0
172#endif
173
174/* The group of references between that reuse may occur. */
175
176struct mem_ref_group
177{
178 tree base; /* Base of the reference. */
179 HOST_WIDE_INT step; /* Step of the reference. */
180 struct mem_ref *refs; /* References in the group. */
181 struct mem_ref_group *next; /* Next group of references. */
182};
183
184/* Assigned to PREFETCH_BEFORE when all iterations are to be prefetched. */
185
186#define PREFETCH_ALL (~(unsigned HOST_WIDE_INT) 0)
187
188/* The memory reference. */
189
190struct mem_ref
191{
192 tree stmt; /* Statement in that the reference appears. */
193 tree mem; /* The reference. */
194 HOST_WIDE_INT delta; /* Constant offset of the reference. */
195 bool write_p; /* Is it a write? */
196 struct mem_ref_group *group; /* The group of references it belongs to. */
197 unsigned HOST_WIDE_INT prefetch_mod;
198 /* Prefetch only each PREFETCH_MOD-th
199 iteration. */
200 unsigned HOST_WIDE_INT prefetch_before;
201 /* Prefetch only first PREFETCH_BEFORE
202 iterations. */
203 bool issue_prefetch_p; /* Should we really issue the prefetch? */
204 struct mem_ref *next; /* The next reference in the group. */
205};
206
75c40d56 207/* Dumps information about reference REF to FILE. */
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208
209static void
210dump_mem_ref (FILE *file, struct mem_ref *ref)
211{
212 fprintf (file, "Reference %p:\n", (void *) ref);
213
214 fprintf (file, " group %p (base ", (void *) ref->group);
215 print_generic_expr (file, ref->group->base, TDF_SLIM);
216 fprintf (file, ", step ");
217 fprintf (file, HOST_WIDE_INT_PRINT_DEC, ref->group->step);
218 fprintf (file, ")\n");
219
220 fprintf (dump_file, " delta ");
221 fprintf (file, HOST_WIDE_INT_PRINT_DEC, ref->delta);
222 fprintf (file, "\n");
223
224 fprintf (file, " %s\n", ref->write_p ? "write" : "read");
225
226 fprintf (file, "\n");
227}
228
229/* Finds a group with BASE and STEP in GROUPS, or creates one if it does not
230 exist. */
231
232static struct mem_ref_group *
233find_or_create_group (struct mem_ref_group **groups, tree base,
234 HOST_WIDE_INT step)
235{
236 struct mem_ref_group *group;
237
238 for (; *groups; groups = &(*groups)->next)
239 {
240 if ((*groups)->step == step
241 && operand_equal_p ((*groups)->base, base, 0))
242 return *groups;
243
244 /* Keep the list of groups sorted by decreasing step. */
245 if ((*groups)->step < step)
246 break;
247 }
248
249 group = xcalloc (1, sizeof (struct mem_ref_group));
250 group->base = base;
251 group->step = step;
252 group->refs = NULL;
253 group->next = *groups;
254 *groups = group;
255
256 return group;
257}
258
259/* Records a memory reference MEM in GROUP with offset DELTA and write status
260 WRITE_P. The reference occurs in statement STMT. */
261
262static void
263record_ref (struct mem_ref_group *group, tree stmt, tree mem,
264 HOST_WIDE_INT delta, bool write_p)
265{
266 struct mem_ref **aref;
267
268 /* Do not record the same address twice. */
269 for (aref = &group->refs; *aref; aref = &(*aref)->next)
270 {
271 /* It does not have to be possible for write reference to reuse the read
272 prefetch, or vice versa. */
273 if (!WRITE_CAN_USE_READ_PREFETCH
274 && write_p
275 && !(*aref)->write_p)
276 continue;
277 if (!READ_CAN_USE_WRITE_PREFETCH
278 && !write_p
279 && (*aref)->write_p)
280 continue;
281
282 if ((*aref)->delta == delta)
283 return;
284 }
285
286 (*aref) = xcalloc (1, sizeof (struct mem_ref));
287 (*aref)->stmt = stmt;
288 (*aref)->mem = mem;
289 (*aref)->delta = delta;
290 (*aref)->write_p = write_p;
291 (*aref)->prefetch_before = PREFETCH_ALL;
292 (*aref)->prefetch_mod = 1;
293 (*aref)->issue_prefetch_p = false;
294 (*aref)->group = group;
295 (*aref)->next = NULL;
296
297 if (dump_file && (dump_flags & TDF_DETAILS))
298 dump_mem_ref (dump_file, *aref);
299}
300
301/* Release memory references in GROUPS. */
302
303static void
304release_mem_refs (struct mem_ref_group *groups)
305{
306 struct mem_ref_group *next_g;
307 struct mem_ref *ref, *next_r;
308
309 for (; groups; groups = next_g)
310 {
311 next_g = groups->next;
312 for (ref = groups->refs; ref; ref = next_r)
313 {
314 next_r = ref->next;
315 free (ref);
316 }
317 free (groups);
318 }
319}
320
321/* A structure used to pass arguments to idx_analyze_ref. */
322
323struct ar_data
324{
325 struct loop *loop; /* Loop of the reference. */
326 tree stmt; /* Statement of the reference. */
327 HOST_WIDE_INT *step; /* Step of the memory reference. */
328 HOST_WIDE_INT *delta; /* Offset of the memory reference. */
329};
330
331/* Analyzes a single INDEX of a memory reference to obtain information
332 described at analyze_ref. Callback for for_each_index. */
333
334static bool
335idx_analyze_ref (tree base, tree *index, void *data)
336{
337 struct ar_data *ar_data = data;
338 tree ibase, step, stepsize;
339 HOST_WIDE_INT istep, idelta = 0, imult = 1;
340 affine_iv iv;
341
342 if (TREE_CODE (base) == MISALIGNED_INDIRECT_REF
343 || TREE_CODE (base) == ALIGN_INDIRECT_REF)
344 return false;
345
346 if (!simple_iv (ar_data->loop, ar_data->stmt, *index, &iv, false))
347 return false;
348 ibase = iv.base;
349 step = iv.step;
350
351 if (zero_p (step))
352 istep = 0;
353 else
354 {
355 if (!cst_and_fits_in_hwi (step))
356 return false;
357 istep = int_cst_value (step);
358 }
359
360 if (TREE_CODE (ibase) == PLUS_EXPR
361 && cst_and_fits_in_hwi (TREE_OPERAND (ibase, 1)))
362 {
363 idelta = int_cst_value (TREE_OPERAND (ibase, 1));
364 ibase = TREE_OPERAND (ibase, 0);
365 }
366 if (cst_and_fits_in_hwi (ibase))
367 {
368 idelta += int_cst_value (ibase);
ff5e9a94 369 ibase = build_int_cst (TREE_TYPE (ibase), 0);
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370 }
371
372 if (TREE_CODE (base) == ARRAY_REF)
373 {
374 stepsize = array_ref_element_size (base);
375 if (!cst_and_fits_in_hwi (stepsize))
376 return false;
377 imult = int_cst_value (stepsize);
378
379 istep *= imult;
380 idelta *= imult;
381 }
382
383 *ar_data->step += istep;
384 *ar_data->delta += idelta;
385 *index = ibase;
386
387 return true;
388}
389
aac8b8ed 390/* Tries to express REF_P in shape &BASE + STEP * iter + DELTA, where DELTA and
b076a3fd 391 STEP are integer constants and iter is number of iterations of LOOP. The
aac8b8ed
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392 reference occurs in statement STMT. Strips nonaddressable component
393 references from REF_P. */
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394
395static bool
aac8b8ed 396analyze_ref (struct loop *loop, tree *ref_p, tree *base,
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397 HOST_WIDE_INT *step, HOST_WIDE_INT *delta,
398 tree stmt)
399{
400 struct ar_data ar_data;
401 tree off;
402 HOST_WIDE_INT bit_offset;
aac8b8ed 403 tree ref = *ref_p;
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404
405 *step = 0;
406 *delta = 0;
407
408 /* First strip off the component references. Ignore bitfields. */
409 if (TREE_CODE (ref) == COMPONENT_REF
410 && DECL_NONADDRESSABLE_P (TREE_OPERAND (ref, 1)))
411 ref = TREE_OPERAND (ref, 0);
412
aac8b8ed
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413 *ref_p = ref;
414
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415 for (; TREE_CODE (ref) == COMPONENT_REF; ref = TREE_OPERAND (ref, 0))
416 {
417 off = DECL_FIELD_BIT_OFFSET (TREE_OPERAND (ref, 1));
418 bit_offset = TREE_INT_CST_LOW (off);
419 gcc_assert (bit_offset % BITS_PER_UNIT == 0);
420
421 *delta += bit_offset / BITS_PER_UNIT;
422 }
423
424 *base = unshare_expr (ref);
425 ar_data.loop = loop;
426 ar_data.stmt = stmt;
427 ar_data.step = step;
428 ar_data.delta = delta;
429 return for_each_index (base, idx_analyze_ref, &ar_data);
430}
431
432/* Record a memory reference REF to the list REFS. The reference occurs in
433 LOOP in statement STMT and it is write if WRITE_P. */
434
435static void
436gather_memory_references_ref (struct loop *loop, struct mem_ref_group **refs,
437 tree ref, bool write_p, tree stmt)
438{
439 tree base;
440 HOST_WIDE_INT step, delta;
441 struct mem_ref_group *agrp;
442
aac8b8ed 443 if (!analyze_ref (loop, &ref, &base, &step, &delta, stmt))
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444 return;
445
446 /* Now we know that REF = &BASE + STEP * iter + DELTA, where DELTA and STEP
447 are integer constants. */
448 agrp = find_or_create_group (refs, base, step);
449 record_ref (agrp, stmt, ref, delta, write_p);
450}
451
452/* Record the suitable memory references in LOOP. */
453
454static struct mem_ref_group *
455gather_memory_references (struct loop *loop)
456{
457 basic_block *body = get_loop_body_in_dom_order (loop);
458 basic_block bb;
459 unsigned i;
460 block_stmt_iterator bsi;
461 tree stmt, lhs, rhs;
462 struct mem_ref_group *refs = NULL;
463
464 /* Scan the loop body in order, so that the former references precede the
465 later ones. */
466 for (i = 0; i < loop->num_nodes; i++)
467 {
468 bb = body[i];
469 if (bb->loop_father != loop)
470 continue;
471
472 for (bsi = bsi_start (bb); !bsi_end_p (bsi); bsi_next (&bsi))
473 {
474 stmt = bsi_stmt (bsi);
475 if (TREE_CODE (stmt) != MODIFY_EXPR)
476 continue;
477
478 lhs = TREE_OPERAND (stmt, 0);
479 rhs = TREE_OPERAND (stmt, 1);
480
481 if (REFERENCE_CLASS_P (rhs))
482 gather_memory_references_ref (loop, &refs, rhs, false, stmt);
483 if (REFERENCE_CLASS_P (lhs))
484 gather_memory_references_ref (loop, &refs, lhs, true, stmt);
485 }
486 }
487 free (body);
488
489 return refs;
490}
491
492/* Prune the prefetch candidate REF using the self-reuse. */
493
494static void
495prune_ref_by_self_reuse (struct mem_ref *ref)
496{
497 HOST_WIDE_INT step = ref->group->step;
498 bool backward = step < 0;
499
500 if (step == 0)
501 {
502 /* Prefetch references to invariant address just once. */
503 ref->prefetch_before = 1;
504 return;
505 }
506
507 if (backward)
508 step = -step;
509
510 if (step > PREFETCH_BLOCK)
511 return;
512
513 if ((backward && HAVE_BACKWARD_PREFETCH)
514 || (!backward && HAVE_FORWARD_PREFETCH))
515 {
516 ref->prefetch_before = 1;
517 return;
518 }
519
520 ref->prefetch_mod = PREFETCH_BLOCK / step;
521}
522
523/* Divides X by BY, rounding down. */
524
525static HOST_WIDE_INT
526ddown (HOST_WIDE_INT x, unsigned HOST_WIDE_INT by)
527{
528 gcc_assert (by > 0);
529
530 if (x >= 0)
531 return x / by;
532 else
533 return (x + by - 1) / by;
534}
535
536/* Prune the prefetch candidate REF using the reuse with BY.
537 If BY_IS_BEFORE is true, BY is before REF in the loop. */
538
539static void
540prune_ref_by_group_reuse (struct mem_ref *ref, struct mem_ref *by,
541 bool by_is_before)
542{
543 HOST_WIDE_INT step = ref->group->step;
544 bool backward = step < 0;
545 HOST_WIDE_INT delta_r = ref->delta, delta_b = by->delta;
546 HOST_WIDE_INT delta = delta_b - delta_r;
547 HOST_WIDE_INT hit_from;
548 unsigned HOST_WIDE_INT prefetch_before, prefetch_block;
549
550 if (delta == 0)
551 {
552 /* If the references has the same address, only prefetch the
553 former. */
554 if (by_is_before)
555 ref->prefetch_before = 0;
556
557 return;
558 }
559
560 if (!step)
561 {
562 /* If the reference addresses are invariant and fall into the
563 same cache line, prefetch just the first one. */
564 if (!by_is_before)
565 return;
566
567 if (ddown (ref->delta, PREFETCH_BLOCK)
568 != ddown (by->delta, PREFETCH_BLOCK))
569 return;
570
571 ref->prefetch_before = 0;
572 return;
573 }
574
575 /* Only prune the reference that is behind in the array. */
576 if (backward)
577 {
578 if (delta > 0)
579 return;
580
581 /* Transform the data so that we may assume that the accesses
582 are forward. */
583 delta = - delta;
584 step = -step;
585 delta_r = PREFETCH_BLOCK - 1 - delta_r;
586 delta_b = PREFETCH_BLOCK - 1 - delta_b;
587 }
588 else
589 {
590 if (delta < 0)
591 return;
592 }
593
594 /* Check whether the two references are likely to hit the same cache
595 line, and how distant the iterations in that it occurs are from
596 each other. */
597
598 if (step <= PREFETCH_BLOCK)
599 {
600 /* The accesses are sure to meet. Let us check when. */
601 hit_from = ddown (delta_b, PREFETCH_BLOCK) * PREFETCH_BLOCK;
602 prefetch_before = (hit_from - delta_r + step - 1) / step;
603
604 if (prefetch_before < ref->prefetch_before)
605 ref->prefetch_before = prefetch_before;
606
607 return;
608 }
609
610 /* A more complicated case. First let us ensure that size of cache line
611 and step are coprime (here we assume that PREFETCH_BLOCK is a power
612 of two. */
613 prefetch_block = PREFETCH_BLOCK;
614 while ((step & 1) == 0
615 && prefetch_block > 1)
616 {
617 step >>= 1;
618 prefetch_block >>= 1;
619 delta >>= 1;
620 }
621
622 /* Now step > prefetch_block, and step and prefetch_block are coprime.
623 Determine the probability that the accesses hit the same cache line. */
624
625 prefetch_before = delta / step;
626 delta %= step;
627 if ((unsigned HOST_WIDE_INT) delta
628 <= (prefetch_block * ACCEPTABLE_MISS_RATE / 1000))
629 {
630 if (prefetch_before < ref->prefetch_before)
631 ref->prefetch_before = prefetch_before;
632
633 return;
634 }
635
636 /* Try also the following iteration. */
637 prefetch_before++;
638 delta = step - delta;
639 if ((unsigned HOST_WIDE_INT) delta
640 <= (prefetch_block * ACCEPTABLE_MISS_RATE / 1000))
641 {
642 if (prefetch_before < ref->prefetch_before)
643 ref->prefetch_before = prefetch_before;
644
645 return;
646 }
647
648 /* The ref probably does not reuse by. */
649 return;
650}
651
652/* Prune the prefetch candidate REF using the reuses with other references
653 in REFS. */
654
655static void
656prune_ref_by_reuse (struct mem_ref *ref, struct mem_ref *refs)
657{
658 struct mem_ref *prune_by;
659 bool before = true;
660
661 prune_ref_by_self_reuse (ref);
662
663 for (prune_by = refs; prune_by; prune_by = prune_by->next)
664 {
665 if (prune_by == ref)
666 {
667 before = false;
668 continue;
669 }
670
671 if (!WRITE_CAN_USE_READ_PREFETCH
672 && ref->write_p
673 && !prune_by->write_p)
674 continue;
675 if (!READ_CAN_USE_WRITE_PREFETCH
676 && !ref->write_p
677 && prune_by->write_p)
678 continue;
679
680 prune_ref_by_group_reuse (ref, prune_by, before);
681 }
682}
683
684/* Prune the prefetch candidates in GROUP using the reuse analysis. */
685
686static void
687prune_group_by_reuse (struct mem_ref_group *group)
688{
689 struct mem_ref *ref_pruned;
690
691 for (ref_pruned = group->refs; ref_pruned; ref_pruned = ref_pruned->next)
692 {
693 prune_ref_by_reuse (ref_pruned, group->refs);
694
695 if (dump_file && (dump_flags & TDF_DETAILS))
696 {
697 fprintf (dump_file, "Reference %p:", (void *) ref_pruned);
698
699 if (ref_pruned->prefetch_before == PREFETCH_ALL
700 && ref_pruned->prefetch_mod == 1)
701 fprintf (dump_file, " no restrictions");
702 else if (ref_pruned->prefetch_before == 0)
703 fprintf (dump_file, " do not prefetch");
704 else if (ref_pruned->prefetch_before <= ref_pruned->prefetch_mod)
705 fprintf (dump_file, " prefetch once");
706 else
707 {
708 if (ref_pruned->prefetch_before != PREFETCH_ALL)
709 {
710 fprintf (dump_file, " prefetch before ");
711 fprintf (dump_file, HOST_WIDE_INT_PRINT_DEC,
712 ref_pruned->prefetch_before);
713 }
714 if (ref_pruned->prefetch_mod != 1)
715 {
716 fprintf (dump_file, " prefetch mod ");
717 fprintf (dump_file, HOST_WIDE_INT_PRINT_DEC,
718 ref_pruned->prefetch_mod);
719 }
720 }
721 fprintf (dump_file, "\n");
722 }
723 }
724}
725
726/* Prune the list of prefetch candidates GROUPS using the reuse analysis. */
727
728static void
729prune_by_reuse (struct mem_ref_group *groups)
730{
731 for (; groups; groups = groups->next)
732 prune_group_by_reuse (groups);
733}
734
735/* Returns true if we should issue prefetch for REF. */
736
737static bool
738should_issue_prefetch_p (struct mem_ref *ref)
739{
740 /* For now do not issue prefetches for only first few of the
741 iterations. */
742 if (ref->prefetch_before != PREFETCH_ALL)
743 return false;
744
745 return true;
746}
747
748/* Decide which of the prefetch candidates in GROUPS to prefetch.
749 AHEAD is the number of iterations to prefetch ahead (which corresponds
750 to the number of simultaneous instances of one prefetch running at a
751 time). UNROLL_FACTOR is the factor by that the loop is going to be
752 unrolled. Returns true if there is anything to prefetch. */
753
754static bool
755schedule_prefetches (struct mem_ref_group *groups, unsigned unroll_factor,
756 unsigned ahead)
757{
758 unsigned max_prefetches, n_prefetches;
759 struct mem_ref *ref;
760 bool any = false;
761
762 max_prefetches = (SIMULTANEOUS_PREFETCHES * unroll_factor) / ahead;
763 if (max_prefetches > (unsigned) SIMULTANEOUS_PREFETCHES)
764 max_prefetches = SIMULTANEOUS_PREFETCHES;
765
766 if (dump_file && (dump_flags & TDF_DETAILS))
767 fprintf (dump_file, "Max prefetches to issue: %d.\n", max_prefetches);
768
769 if (!max_prefetches)
770 return false;
771
772 /* For now we just take memory references one by one and issue
773 prefetches for as many as possible. The groups are sorted
774 starting with the largest step, since the references with
c0220ea4 775 large step are more likely to cause many cache misses. */
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776
777 for (; groups; groups = groups->next)
778 for (ref = groups->refs; ref; ref = ref->next)
779 {
780 if (!should_issue_prefetch_p (ref))
781 continue;
782
783 ref->issue_prefetch_p = true;
784
785 /* If prefetch_mod is less then unroll_factor, we need to insert
786 several prefetches for the reference. */
787 n_prefetches = ((unroll_factor + ref->prefetch_mod - 1)
788 / ref->prefetch_mod);
789 if (max_prefetches <= n_prefetches)
790 return true;
791
792 max_prefetches -= n_prefetches;
793 any = true;
794 }
795
796 return any;
797}
798
799/* Determine whether there is any reference suitable for prefetching
800 in GROUPS. */
801
802static bool
803anything_to_prefetch_p (struct mem_ref_group *groups)
804{
805 struct mem_ref *ref;
806
807 for (; groups; groups = groups->next)
808 for (ref = groups->refs; ref; ref = ref->next)
809 if (should_issue_prefetch_p (ref))
810 return true;
811
812 return false;
813}
814
815/* Issue prefetches for the reference REF into loop as decided before.
816 HEAD is the number of iterations to prefetch ahead. UNROLL_FACTOR
917f1b7e 817 is the factor by which LOOP was unrolled. */
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818
819static void
820issue_prefetch_ref (struct mem_ref *ref, unsigned unroll_factor, unsigned ahead)
821{
822 HOST_WIDE_INT delta;
823 tree addr, addr_base, prefetch, params, write_p;
824 block_stmt_iterator bsi;
825 unsigned n_prefetches, ap;
826
827 if (dump_file && (dump_flags & TDF_DETAILS))
828 fprintf (dump_file, "Issued prefetch for %p.\n", (void *) ref);
829
830 bsi = bsi_for_stmt (ref->stmt);
831
832 n_prefetches = ((unroll_factor + ref->prefetch_mod - 1)
833 / ref->prefetch_mod);
834 addr_base = build_fold_addr_expr_with_type (ref->mem, ptr_type_node);
835 addr_base = force_gimple_operand_bsi (&bsi, unshare_expr (addr_base), true, NULL);
836
837 for (ap = 0; ap < n_prefetches; ap++)
838 {
839 /* Determine the address to prefetch. */
840 delta = (ahead + ap * ref->prefetch_mod) * ref->group->step;
841 addr = fold_build2 (PLUS_EXPR, ptr_type_node,
842 addr_base, build_int_cst (ptr_type_node, delta));
843 addr = force_gimple_operand_bsi (&bsi, unshare_expr (addr), true, NULL);
844
845 /* Create the prefetch instruction. */
846 write_p = ref->write_p ? integer_one_node : integer_zero_node;
847 params = tree_cons (NULL_TREE, addr,
848 tree_cons (NULL_TREE, write_p, NULL_TREE));
849
850 prefetch = build_function_call_expr (built_in_decls[BUILT_IN_PREFETCH],
851 params);
852 bsi_insert_before (&bsi, prefetch, BSI_SAME_STMT);
853 }
854}
855
856/* Issue prefetches for the references in GROUPS into loop as decided before.
857 HEAD is the number of iterations to prefetch ahead. UNROLL_FACTOR is the
858 factor by that LOOP was unrolled. */
859
860static void
861issue_prefetches (struct mem_ref_group *groups,
862 unsigned unroll_factor, unsigned ahead)
863{
864 struct mem_ref *ref;
865
866 for (; groups; groups = groups->next)
867 for (ref = groups->refs; ref; ref = ref->next)
868 if (ref->issue_prefetch_p)
869 issue_prefetch_ref (ref, unroll_factor, ahead);
870}
871
872/* Determines whether we can profitably unroll LOOP FACTOR times, and if
873 this is the case, fill in DESC by the description of number of
874 iterations. */
875
876static bool
877should_unroll_loop_p (struct loop *loop, struct tree_niter_desc *desc,
878 unsigned factor)
879{
880 if (!can_unroll_loop_p (loop, factor, desc))
881 return false;
882
883 /* We only consider loops without control flow for unrolling. This is not
884 a hard restriction -- tree_unroll_loop works with arbitrary loops
885 as well; but the unrolling/prefetching is usually more profitable for
886 loops consisting of a single basic block, and we want to limit the
887 code growth. */
888 if (loop->num_nodes > 2)
889 return false;
890
891 return true;
892}
893
894/* Determine the coefficient by that unroll LOOP, from the information
895 contained in the list of memory references REFS. Description of
896 umber of iterations of LOOP is stored to DESC. AHEAD is the number
897 of iterations ahead that we need to prefetch. NINSNS is number of
898 insns of the LOOP. */
899
900static unsigned
901determine_unroll_factor (struct loop *loop, struct mem_ref_group *refs,
902 unsigned ahead, unsigned ninsns,
903 struct tree_niter_desc *desc)
904{
905 unsigned upper_bound, size_factor, constraint_factor;
906 unsigned factor, max_mod_constraint, ahead_factor;
907 struct mem_ref_group *agp;
908 struct mem_ref *ref;
909
910 upper_bound = PARAM_VALUE (PARAM_MAX_UNROLL_TIMES);
911
912 /* First check whether the loop is not too large to unroll. */
913 size_factor = PARAM_VALUE (PARAM_MAX_UNROLLED_INSNS) / ninsns;
914 if (size_factor <= 1)
915 return 1;
916
917 if (size_factor < upper_bound)
918 upper_bound = size_factor;
919
920 max_mod_constraint = 1;
921 for (agp = refs; agp; agp = agp->next)
922 for (ref = agp->refs; ref; ref = ref->next)
923 if (should_issue_prefetch_p (ref)
924 && ref->prefetch_mod > max_mod_constraint)
925 max_mod_constraint = ref->prefetch_mod;
926
927 /* Set constraint_factor as large as needed to be able to satisfy the
928 largest modulo constraint. */
929 constraint_factor = max_mod_constraint;
930
931 /* If ahead is too large in comparison with the number of available
932 prefetches, unroll the loop as much as needed to be able to prefetch
933 at least partially some of the references in the loop. */
934 ahead_factor = ((ahead + SIMULTANEOUS_PREFETCHES - 1)
935 / SIMULTANEOUS_PREFETCHES);
936
937 /* Unroll as much as useful, but bound the code size growth. */
938 if (constraint_factor < ahead_factor)
939 factor = ahead_factor;
940 else
941 factor = constraint_factor;
942 if (factor > upper_bound)
943 factor = upper_bound;
944
945 if (!should_unroll_loop_p (loop, desc, factor))
946 return 1;
947
948 return factor;
949}
950
951/* Issue prefetch instructions for array references in LOOP. Returns
952 true if the LOOP was unrolled. LOOPS is the array containing all
953 loops. */
954
955static bool
956loop_prefetch_arrays (struct loops *loops, struct loop *loop)
957{
958 struct mem_ref_group *refs;
959 unsigned ahead, ninsns, unroll_factor;
960 struct tree_niter_desc desc;
961 bool unrolled = false;
962
963 /* Step 1: gather the memory references. */
964 refs = gather_memory_references (loop);
965
966 /* Step 2: estimate the reuse effects. */
967 prune_by_reuse (refs);
968
969 if (!anything_to_prefetch_p (refs))
970 goto fail;
971
972 /* Step 3: determine the ahead and unroll factor. */
973
974 /* FIXME: We should use not size of the loop, but the average number of
975 instructions executed per iteration of the loop. */
976 ninsns = tree_num_loop_insns (loop);
977 ahead = (PREFETCH_LATENCY + ninsns - 1) / ninsns;
978 unroll_factor = determine_unroll_factor (loop, refs, ahead, ninsns,
979 &desc);
980 if (dump_file && (dump_flags & TDF_DETAILS))
981 fprintf (dump_file, "Ahead %d, unroll factor %d\n", ahead, unroll_factor);
982
983 /* If the loop rolls less than the required unroll factor, prefetching
984 is useless. */
985 if (unroll_factor > 1
986 && cst_and_fits_in_hwi (desc.niter)
987 && (unsigned HOST_WIDE_INT) int_cst_value (desc.niter) < unroll_factor)
988 goto fail;
989
990 /* Step 4: what to prefetch? */
991 if (!schedule_prefetches (refs, unroll_factor, ahead))
992 goto fail;
993
994 /* Step 5: unroll the loop. TODO -- peeling of first and last few
995 iterations so that we do not issue superfluous prefetches. */
996 if (unroll_factor != 1)
997 {
998 tree_unroll_loop (loops, loop, unroll_factor,
999 single_dom_exit (loop), &desc);
1000 unrolled = true;
1001 }
1002
1003 /* Step 6: issue the prefetches. */
1004 issue_prefetches (refs, unroll_factor, ahead);
1005
1006fail:
1007 release_mem_refs (refs);
1008 return unrolled;
1009}
1010
1011/* Issue prefetch instructions for array references in LOOPS. */
1012
c7f965b6 1013unsigned int
b076a3fd
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1014tree_ssa_prefetch_arrays (struct loops *loops)
1015{
1016 unsigned i;
1017 struct loop *loop;
1018 bool unrolled = false;
c7f965b6 1019 int todo_flags = 0;
b076a3fd
ZD
1020
1021 if (!HAVE_prefetch
1022 /* It is possible to ask compiler for say -mtune=i486 -march=pentium4.
1023 -mtune=i486 causes us having PREFETCH_BLOCK 0, since this is part
1024 of processor costs and i486 does not have prefetch, but
1025 -march=pentium4 causes HAVE_prefetch to be true. Ugh. */
1026 || PREFETCH_BLOCK == 0)
c7f965b6 1027 return 0;
b076a3fd
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1028
1029 initialize_original_copy_tables ();
1030
1031 if (!built_in_decls[BUILT_IN_PREFETCH])
1032 {
1033 tree type = build_function_type (void_type_node,
1034 tree_cons (NULL_TREE,
1035 const_ptr_type_node,
1036 NULL_TREE));
c79efc4d
RÁE
1037 tree decl = add_builtin_function ("__builtin_prefetch", type,
1038 BUILT_IN_PREFETCH, BUILT_IN_NORMAL,
1039 NULL, NULL_TREE);
b076a3fd
ZD
1040 DECL_IS_NOVOPS (decl) = true;
1041 built_in_decls[BUILT_IN_PREFETCH] = decl;
1042 }
1043
1044 /* We assume that size of cache line is a power of two, so verify this
1045 here. */
1046 gcc_assert ((PREFETCH_BLOCK & (PREFETCH_BLOCK - 1)) == 0);
1047
1048 for (i = loops->num - 1; i > 0; i--)
1049 {
1050 loop = loops->parray[i];
1051
1052 if (dump_file && (dump_flags & TDF_DETAILS))
1053 fprintf (dump_file, "Processing loop %d:\n", loop->num);
1054
1055 if (loop)
1056 unrolled |= loop_prefetch_arrays (loops, loop);
1057
1058 if (dump_file && (dump_flags & TDF_DETAILS))
1059 fprintf (dump_file, "\n\n");
1060 }
1061
1062 if (unrolled)
1063 {
1064 scev_reset ();
c7f965b6 1065 todo_flags |= TODO_cleanup_cfg;
b076a3fd
ZD
1066 }
1067
1068 free_original_copy_tables ();
c7f965b6 1069 return todo_flags;
b076a3fd 1070}