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git.ipfire.org Git - thirdparty/glibc.git/blob - sysdeps/ieee754/ldbl-96/e_jnl.c
2 * ====================================================
3 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
5 * Developed at SunPro, a Sun Microsystems, Inc. business.
6 * Permission to use, copy, modify, and distribute this
7 * software is freely granted, provided that this notice
9 * ====================================================
12 /* Modifications for long double are
13 Copyright (C) 2001 Stephen L. Moshier <moshier@na-net.ornl.gov>
14 and are incorporated herein by permission of the author. The author
15 reserves the right to distribute this material elsewhere under different
16 copying permissions. These modifications are distributed here under
19 This library is free software; you can redistribute it and/or
20 modify it under the terms of the GNU Lesser General Public
21 License as published by the Free Software Foundation; either
22 version 2.1 of the License, or (at your option) any later version.
24 This library is distributed in the hope that it will be useful,
25 but WITHOUT ANY WARRANTY; without even the implied warranty of
26 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
27 Lesser General Public License for more details.
29 You should have received a copy of the GNU Lesser General Public
30 License along with this library; if not, write to the Free Software
31 Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA */
34 * __ieee754_jn(n, x), __ieee754_yn(n, x)
35 * floating point Bessel's function of the 1st and 2nd kind
39 * y0(0)=y1(0)=yn(n,0) = -inf with overflow signal;
40 * y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal.
41 * Note 2. About jn(n,x), yn(n,x)
42 * For n=0, j0(x) is called,
43 * for n=1, j1(x) is called,
44 * for n<x, forward recursion us used starting
45 * from values of j0(x) and j1(x).
46 * for n>x, a continued fraction approximation to
47 * j(n,x)/j(n-1,x) is evaluated and then backward
48 * recursion is used starting from a supposed value
49 * for j(n,x). The resulting value of j(0,x) is
50 * compared with the actual value to correct the
51 * supposed value of j(n,x).
53 * yn(n,x) is similar in all respects, except
54 * that forward recursion is used for all
60 #include "math_private.h"
62 static const long double
63 invsqrtpi
= 5.64189583547756286948079e-1L, two
= 2.0e0L
, one
= 1.0e0L
;
65 static const long double zero
= 0.0L;
68 __ieee754_jnl (int n
, long double x
)
72 long double a
, b
, temp
, di
;
75 /* J(-n,x) = (-1)^n * J(n, x), J(n, -x) = (-1)^n * J(n, x)
76 * Thus, J(-n,x) = J(n,-x)
79 GET_LDOUBLE_WORDS (se
, i0
, i1
, x
);
82 /* if J(n,NaN) is NaN */
83 if (__builtin_expect ((ix
== 0x7fff) && ((i0
& 0x7fffffff) != 0), 0))
92 return (__ieee754_j0l (x
));
94 return (__ieee754_j1l (x
));
95 sgn
= (n
& 1) & (se
>> 15); /* even n -- 0, odd n -- sign(x) */
97 if (__builtin_expect ((ix
| i0
| i1
) == 0 || ix
>= 0x7fff, 0))
98 /* if x is 0 or inf */
100 else if ((long double) n
<= x
)
102 /* Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x) */
106 /* ??? This might be a futile gesture.
107 If x exceeds X_TLOSS anyway, the wrapper function
108 will set the result to zero. */
111 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
112 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
113 * Let s=sin(x), c=cos(x),
114 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
116 * n sin(xn)*sqt2 cos(xn)*sqt2
117 * ----------------------------------
125 __sincosl (x
, &s
, &c
);
141 b
= invsqrtpi
* temp
/ __ieee754_sqrtl (x
);
145 a
= __ieee754_j0l (x
);
146 b
= __ieee754_j1l (x
);
147 for (i
= 1; i
< n
; i
++)
150 b
= b
* ((long double) (i
+ i
) / x
) - a
; /* avoid underflow */
159 /* x is tiny, return the first Taylor expansion of J(n,x)
160 * J(n,x) = 1/n!*(x/2)^n - ...
162 if (n
>= 400) /* underflow, result < 10^-4952 */
168 for (a
= one
, i
= 2; i
<= n
; i
++)
170 a
*= (long double) i
; /* a = n! */
171 b
*= temp
; /* b = (x/2)^n */
178 /* use backward recurrence */
180 * J(n,x)/J(n-1,x) = ---- ------ ------ .....
181 * 2n - 2(n+1) - 2(n+2)
184 * (for large x) = ---- ------ ------ .....
186 * -- - ------ - ------ -
189 * Let w = 2n/x and h=2/x, then the above quotient
190 * is equal to the continued fraction:
192 * = -----------------------
194 * w - -----------------
199 * To determine how many terms needed, let
200 * Q(0) = w, Q(1) = w(w+h) - 1,
201 * Q(k) = (w+k*h)*Q(k-1) - Q(k-2),
202 * When Q(k) > 1e4 good for single
203 * When Q(k) > 1e9 good for double
204 * When Q(k) > 1e17 good for quadruple
208 long double q0
, q1
, h
, tmp
;
210 w
= (n
+ n
) / (long double) x
;
211 h
= 2.0L / (long double) x
;
225 for (t
= zero
, i
= 2 * (n
+ k
); i
>= m
; i
-= 2)
226 t
= one
/ (i
/ x
- t
);
229 /* estimate log((2/x)^n*n!) = n*log(2/x)+n*ln(n)
230 * Hence, if n*(log(2n/x)) > ...
231 * single 8.8722839355e+01
232 * double 7.09782712893383973096e+02
233 * long double 1.1356523406294143949491931077970765006170e+04
234 * then recurrent value may overflow and the result is
235 * likely underflow to zero
239 tmp
= tmp
* __ieee754_logl (fabsl (v
* tmp
));
241 if (tmp
< 1.1356523406294143949491931077970765006170e+04L)
243 for (i
= n
- 1, di
= (long double) (i
+ i
); i
> 0; i
--)
254 for (i
= n
- 1, di
= (long double) (i
+ i
); i
> 0; i
--)
261 /* scale b to avoid spurious overflow */
270 /* j0() and j1() suffer enormous loss of precision at and
271 * near zero; however, we know that their zero points never
272 * coincide, so just choose the one further away from zero.
274 z
= __ieee754_j0l (x
);
275 w
= __ieee754_j1l (x
);
276 if (fabsl (z
) >= fabsl (w
))
287 strong_alias (__ieee754_jnl
, __jnl_finite
)
290 __ieee754_ynl (int n
, long double x
)
292 u_int32_t se
, i0
, i1
;
295 long double a
, b
, temp
;
298 GET_LDOUBLE_WORDS (se
, i0
, i1
, x
);
300 /* if Y(n,NaN) is NaN */
301 if (__builtin_expect ((ix
== 0x7fff) && ((i0
& 0x7fffffff) != 0), 0))
303 if (__builtin_expect ((ix
| i0
| i1
) == 0, 0))
304 return -HUGE_VALL
+ x
; /* -inf and overflow exception. */
305 if (__builtin_expect (se
& 0x8000, 0))
306 return zero
/ (zero
* x
);
311 sign
= 1 - ((n
& 1) << 1);
314 return (__ieee754_y0l (x
));
316 return (sign
* __ieee754_y1l (x
));
317 if (__builtin_expect (ix
== 0x7fff, 0))
322 /* ??? See comment above on the possible futility of this. */
325 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
326 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
327 * Let s=sin(x), c=cos(x),
328 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
330 * n sin(xn)*sqt2 cos(xn)*sqt2
331 * ----------------------------------
339 __sincosl (x
, &s
, &c
);
355 b
= invsqrtpi
* temp
/ __ieee754_sqrtl (x
);
359 a
= __ieee754_y0l (x
);
360 b
= __ieee754_y1l (x
);
361 /* quit if b is -inf */
362 GET_LDOUBLE_WORDS (se
, i0
, i1
, b
);
363 for (i
= 1; i
< n
&& se
!= 0xffff; i
++)
366 b
= ((long double) (i
+ i
) / x
) * b
- a
;
367 GET_LDOUBLE_WORDS (se
, i0
, i1
, b
);
376 strong_alias (__ieee754_ynl
, __ynl_finite
)