Update copyright dates with scripts/update-copyrights.

[thirdparty/glibc.git] / stdlib / ldiv.c

diff --git a/stdlib/ldiv.c b/stdlib/ldiv.c
index 36681df47e04468b6cf38719fa9557daba4260de..433e7fc3dfb3eb0032ee6e9d718eb4fcf6f6ec4a 100644 (file)
--- a/stdlib/ldiv.c
+++ b/stdlib/ldiv.c
@@ -1,4 +1,4 @@
-/* Copyright (C) 1992, 1997 Free Software Foundation, Inc.
+/* Copyright (C) 1992-2016 Free Software Foundation, Inc.
    This file is part of the GNU C Library.
 
    The GNU C Library is free software; you can redistribute it and/or
@@ -27,27 +27,5 @@ ldiv (long int numer, long int denom)
   result.quot = numer / denom;
   result.rem = numer % denom;
 
-  /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
-     NUMER / DENOM is to be computed in infinite precision.  In
-     other words, we should always truncate the quotient towards
-     zero, never -infinity.  Machine division and remainer may
-     work either way when one or both of NUMER or DENOM is
-     negative.  If only one is negative and QUOT has been
-     truncated towards -infinity, REM will have the same sign as
-     DENOM and the opposite sign of NUMER; if both are negative
-     and QUOT has been truncated towards -infinity, REM will be
-     positive (will have the opposite sign of NUMER).  These are
-     considered `wrong'.  If both are NUM and DENOM are positive,
-     RESULT will always be positive.  This all boils down to: if
-     NUMER >= 0, but REM < 0, we got the wrong answer.  In that
-     case, to get the right answer, add 1 to QUOT and subtract
-     DENOM from REM.  */
-
-  if (numer >= 0 && result.rem < 0)
-    {
-      ++result.quot;
-      result.rem -= denom;
-    }
-
   return result;
 }