[powerpc] No need to enter "Ignore Exceptions Mode"

[thirdparty/glibc.git] / stdlib / ldiv.c

diff --git a/stdlib/ldiv.c b/stdlib/ldiv.c
index 76d474fc62b241f16536a2a08d10cfcb6ae66e3b..ef4d45239707f098a520e26301f72941835d9039 100644 (file)
--- a/stdlib/ldiv.c
+++ b/stdlib/ldiv.c
@@ -1,4 +1,4 @@
-/* Copyright (C) 1992-2013 Free Software Foundation, Inc.
+/* Copyright (C) 1992-2019 Free Software Foundation, Inc.
    This file is part of the GNU C Library.
 
    The GNU C Library is free software; you can redistribute it and/or
@@ -13,7 +13,7 @@
 
    You should have received a copy of the GNU Lesser General Public
    License along with the GNU C Library; if not, see
-   <http://www.gnu.org/licenses/>.  */
+   <https://www.gnu.org/licenses/>.  */
 
 #include <stdlib.h>
 
@@ -27,27 +27,5 @@ ldiv (long int numer, long int denom)
   result.quot = numer / denom;
   result.rem = numer % denom;
 
-  /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
-     NUMER / DENOM is to be computed in infinite precision.  In
-     other words, we should always truncate the quotient towards
-     zero, never -infinity.  Machine division and remainer may
-     work either way when one or both of NUMER or DENOM is
-     negative.  If only one is negative and QUOT has been
-     truncated towards -infinity, REM will have the same sign as
-     DENOM and the opposite sign of NUMER; if both are negative
-     and QUOT has been truncated towards -infinity, REM will be
-     positive (will have the opposite sign of NUMER).  These are
-     considered `wrong'.  If both are NUM and DENOM are positive,
-     RESULT will always be positive.  This all boils down to: if
-     NUMER >= 0, but REM < 0, we got the wrong answer.  In that
-     case, to get the right answer, add 1 to QUOT and subtract
-     DENOM from REM.  */
-
-  if (numer >= 0 && result.rem < 0)
-    {
-      ++result.quot;
-      result.rem -= denom;
-    }
-
   return result;
 }