python-pycurl/python-pycurl.nm

   1 ###############################################################################
   2 # IPFire.org    - An Open Source Firewall Solution                            #
   3 # Copyright (C) - IPFire Development Team <info@ipfire.org>                   #
   4 ###############################################################################
   5
   6 name       = python-pycurl
   7 version    = 7.19.0
   8 release    = 5
   9 thisapp    = pycurl-%{version}
  10
  11 groups     = Development/Languages
  12 url        = http://pycurl.sourceforge.net/
  13 license    = LGPLv2+ or MIT
  14 summary    = A Python interface to libcurl.
  15
  16 description
  17         PycURL is a Python interface to libcurl. PycURL can be used to fetch
  18         objects identified by a URL from a Python program, similar to the
  19         urllib Python module. PycURL is mature, very fast, and supports a lot
  20         of features.
  21 end
  22
  23 source_dl  = http://pycurl.sourceforge.net/download/
  24
  25 build
  26         requires
  27                 libcurl-devel
  28                 openssl-devel
  29                 python-devel
  30         end
  31
  32         CFLAGS += -DHAVE_CURL_OPENSSL
  33
  34         build
  35                 python setup.py build
  36         end
  37
  38         test
  39                 PYTHONPATH=$PWD/build/lib* python tests/test_internals.py -q
  40         end
  41
  42         install
  43                 python setup.py install --skip-build -O1 \
  44                         --root=%{BUILDROOT}
  45                 rm -rf %{BUILDROOT}/usr/share/doc/pycurl
  46         end
  47 end
  48
  49 packages
  50         package %{name}
  51                 # During its initialization, PycURL checks that the actual libcurl version
  52                 # is not lower than the one used when PycURL was built.
  53                 # Yes, that should be handled by library versioning (which would then get
  54                 # automatically reflected).
  55                 # For now, we have to reflect that dependency.
  56                 requires
  57                         libcurl >= %(curl-config --version | awk '{ print $NF }')
  58                 end
  59         end
  60
  61         package %{name}-debuginfo
  62                 template DEBUGINFO
  63         end
  64 end