The tree-cfg.cc verifier only diagnoses returns_twice calls preceded
by non-label/debug stmts if it is in a bb with abnormal predecessor.
The following testcase shows that if a user lies in the attributes
(a function which never returns can't be pure, and can't return
twice when it doesn't ever return at all), when we figure it out,
we can remove the abnormal edges to the "returns_twice" call and perhaps
whole .ABNORMAL_DISPATCHER etc.
edge_before_returns_twice_call then ICEs because it can't find such
an edge.
The following patch limits the special handling to calls in bbs where
the verifier requires that.
2024-04-12 Jakub Jelinek <jakub@redhat.com>
PR sanitizer/114687
* gimple-iterator.cc (gsi_safe_insert_before): Only use
edge_before_returns_twice_call if bb_has_abnormal_pred.
(gsi_safe_insert_seq_before): Likewise.
* gimple-lower-bitint.cc (bitint_large_huge::lower_call): Only
push to m_returns_twice_calls if bb_has_abnormal_pred.
* gcc.dg/asan/pr114687.c: New test.
gimple *stmt = gsi_stmt (*iter);
if (stmt
&& is_gimple_call (stmt)
- && (gimple_call_flags (stmt) & ECF_RETURNS_TWICE) != 0)
+ && (gimple_call_flags (stmt) & ECF_RETURNS_TWICE) != 0
+ && bb_has_abnormal_pred (gsi_bb (*iter)))
{
edge e = edge_before_returns_twice_call (gsi_bb (*iter));
basic_block new_bb = gsi_insert_on_edge_immediate (e, g);
gimple *stmt = gsi_stmt (*iter);
if (stmt
&& is_gimple_call (stmt)
- && (gimple_call_flags (stmt) & ECF_RETURNS_TWICE) != 0)
+ && (gimple_call_flags (stmt) & ECF_RETURNS_TWICE) != 0
+ && bb_has_abnormal_pred (gsi_bb (*iter)))
{
edge e = edge_before_returns_twice_call (gsi_bb (*iter));
gimple *f = gimple_seq_first_stmt (seq);
arg = make_ssa_name (TREE_TYPE (arg));
gimple *g = gimple_build_assign (arg, v);
gsi_insert_before (&gsi, g, GSI_SAME_STMT);
- if (returns_twice)
+ if (returns_twice && bb_has_abnormal_pred (gimple_bb (stmt)))
{
m_returns_twice_calls.safe_push (stmt);
returns_twice = false;
--- /dev/null
+/* PR sanitizer/114687 */
+/* { dg-do compile } */
+
+int a;
+int foo (int);
+
+__attribute__((pure, returns_twice)) int
+bar (void)
+{
+ a = 1;
+ while (a)
+ a = 2;
+ return a;
+}
+
+int
+baz (void)
+{
+ int d = bar ();
+ foo (d);
+ return 0;
+}