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1@node Obstacks,Licenses,Functions,Top
2@chapter Obstacks
3@cindex obstacks
4
5An @dfn{obstack} is a pool of memory containing a stack of objects. You
6can create any number of separate obstacks, and then allocate objects in
7specified obstacks. Within each obstack, the last object allocated must
8always be the first one freed, but distinct obstacks are independent of
9each other.
10
11Aside from this one constraint of order of freeing, obstacks are totally
12general: an obstack can contain any number of objects of any size. They
13are implemented with macros, so allocation is usually very fast as long as
14the objects are usually small. And the only space overhead per object is
15the padding needed to start each object on a suitable boundary.
16
17@menu
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18* Creating Obstacks:: How to declare an obstack in your program.
19* Preparing for Obstacks:: Preparations needed before you can
20 use obstacks.
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21* Allocation in an Obstack:: Allocating objects in an obstack.
22* Freeing Obstack Objects:: Freeing objects in an obstack.
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23* Obstack Functions:: The obstack functions are both
24 functions and macros.
39423523 25* Growing Objects:: Making an object bigger by stages.
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26* Extra Fast Growing:: Extra-high-efficiency (though more
27 complicated) growing objects.
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28* Status of an Obstack:: Inquiries about the status of an obstack.
29* Obstacks Data Alignment:: Controlling alignment of objects in obstacks.
30* Obstack Chunks:: How obstacks obtain and release chunks;
83ef53a9 31 efficiency considerations.
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32* Summary of Obstacks::
33@end menu
34
35@node Creating Obstacks
36@section Creating Obstacks
37
38The utilities for manipulating obstacks are declared in the header
39file @file{obstack.h}.
40@pindex obstack.h
41
42@comment obstack.h
43@comment GNU
44@deftp {Data Type} {struct obstack}
45An obstack is represented by a data structure of type @code{struct
46obstack}. This structure has a small fixed size; it records the status
47of the obstack and how to find the space in which objects are allocated.
48It does not contain any of the objects themselves. You should not try
49to access the contents of the structure directly; use only the functions
50described in this chapter.
51@end deftp
52
53You can declare variables of type @code{struct obstack} and use them as
54obstacks, or you can allocate obstacks dynamically like any other kind
55of object. Dynamic allocation of obstacks allows your program to have a
56variable number of different stacks. (You can even allocate an
57obstack structure in another obstack, but this is rarely useful.)
58
59All the functions that work with obstacks require you to specify which
60obstack to use. You do this with a pointer of type @code{struct obstack
61*}. In the following, we often say ``an obstack'' when strictly
62speaking the object at hand is such a pointer.
63
64The objects in the obstack are packed into large blocks called
65@dfn{chunks}. The @code{struct obstack} structure points to a chain of
66the chunks currently in use.
67
68The obstack library obtains a new chunk whenever you allocate an object
69that won't fit in the previous chunk. Since the obstack library manages
70chunks automatically, you don't need to pay much attention to them, but
71you do need to supply a function which the obstack library should use to
72get a chunk. Usually you supply a function which uses @code{malloc}
73directly or indirectly. You must also supply a function to free a chunk.
74These matters are described in the following section.
75
76@node Preparing for Obstacks
77@section Preparing for Using Obstacks
78
79Each source file in which you plan to use the obstack functions
80must include the header file @file{obstack.h}, like this:
81
82@smallexample
83#include <obstack.h>
84@end smallexample
85
86@findex obstack_chunk_alloc
87@findex obstack_chunk_free
88Also, if the source file uses the macro @code{obstack_init}, it must
89declare or define two functions or macros that will be called by the
90obstack library. One, @code{obstack_chunk_alloc}, is used to allocate
91the chunks of memory into which objects are packed. The other,
92@code{obstack_chunk_free}, is used to return chunks when the objects in
93them are freed. These macros should appear before any use of obstacks
94in the source file.
95
96Usually these are defined to use @code{malloc} via the intermediary
97@code{xmalloc} (@pxref{Unconstrained Allocation, , , libc, The GNU C Library Reference Manual}). This is done with
98the following pair of macro definitions:
99
100@smallexample
101#define obstack_chunk_alloc xmalloc
102#define obstack_chunk_free free
103@end smallexample
104
105@noindent
106Though the memory you get using obstacks really comes from @code{malloc},
107using obstacks is faster because @code{malloc} is called less often, for
108larger blocks of memory. @xref{Obstack Chunks}, for full details.
109
110At run time, before the program can use a @code{struct obstack} object
111as an obstack, it must initialize the obstack by calling
112@code{obstack_init}.
113
114@comment obstack.h
115@comment GNU
116@deftypefun int obstack_init (struct obstack *@var{obstack-ptr})
117Initialize obstack @var{obstack-ptr} for allocation of objects. This
118function calls the obstack's @code{obstack_chunk_alloc} function. If
119allocation of memory fails, the function pointed to by
120@code{obstack_alloc_failed_handler} is called. The @code{obstack_init}
121function always returns 1 (Compatibility notice: Former versions of
122obstack returned 0 if allocation failed).
123@end deftypefun
124
125Here are two examples of how to allocate the space for an obstack and
126initialize it. First, an obstack that is a static variable:
127
128@smallexample
129static struct obstack myobstack;
130@dots{}
131obstack_init (&myobstack);
132@end smallexample
133
134@noindent
135Second, an obstack that is itself dynamically allocated:
136
137@smallexample
138struct obstack *myobstack_ptr
139 = (struct obstack *) xmalloc (sizeof (struct obstack));
140
141obstack_init (myobstack_ptr);
142@end smallexample
143
144@comment obstack.h
145@comment GNU
146@defvar obstack_alloc_failed_handler
147The value of this variable is a pointer to a function that
148@code{obstack} uses when @code{obstack_chunk_alloc} fails to allocate
149memory. The default action is to print a message and abort.
150You should supply a function that either calls @code{exit}
151(@pxref{Program Termination, , , libc, The GNU C Library Reference Manual}) or @code{longjmp} (@pxref{Non-Local
152Exits, , , libc, The GNU C Library Reference Manual}) and doesn't return.
153
154@smallexample
155void my_obstack_alloc_failed (void)
156@dots{}
157obstack_alloc_failed_handler = &my_obstack_alloc_failed;
158@end smallexample
159
160@end defvar
161
162@node Allocation in an Obstack
163@section Allocation in an Obstack
164@cindex allocation (obstacks)
165
166The most direct way to allocate an object in an obstack is with
167@code{obstack_alloc}, which is invoked almost like @code{malloc}.
168
169@comment obstack.h
170@comment GNU
171@deftypefun {void *} obstack_alloc (struct obstack *@var{obstack-ptr}, int @var{size})
172This allocates an uninitialized block of @var{size} bytes in an obstack
173and returns its address. Here @var{obstack-ptr} specifies which obstack
174to allocate the block in; it is the address of the @code{struct obstack}
175object which represents the obstack. Each obstack function or macro
176requires you to specify an @var{obstack-ptr} as the first argument.
177
178This function calls the obstack's @code{obstack_chunk_alloc} function if
179it needs to allocate a new chunk of memory; it calls
180@code{obstack_alloc_failed_handler} if allocation of memory by
181@code{obstack_chunk_alloc} failed.
182@end deftypefun
183
184For example, here is a function that allocates a copy of a string @var{str}
185in a specific obstack, which is in the variable @code{string_obstack}:
186
187@smallexample
188struct obstack string_obstack;
189
190char *
191copystring (char *string)
192@{
193 size_t len = strlen (string) + 1;
194 char *s = (char *) obstack_alloc (&string_obstack, len);
195 memcpy (s, string, len);
196 return s;
197@}
198@end smallexample
199
200To allocate a block with specified contents, use the function
201@code{obstack_copy}, declared like this:
202
203@comment obstack.h
204@comment GNU
205@deftypefun {void *} obstack_copy (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
206This allocates a block and initializes it by copying @var{size}
207bytes of data starting at @var{address}. It calls
208@code{obstack_alloc_failed_handler} if allocation of memory by
209@code{obstack_chunk_alloc} failed.
210@end deftypefun
211
212@comment obstack.h
213@comment GNU
214@deftypefun {void *} obstack_copy0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
215Like @code{obstack_copy}, but appends an extra byte containing a null
216character. This extra byte is not counted in the argument @var{size}.
217@end deftypefun
218
219The @code{obstack_copy0} function is convenient for copying a sequence
220of characters into an obstack as a null-terminated string. Here is an
221example of its use:
222
223@smallexample
224char *
225obstack_savestring (char *addr, int size)
226@{
227 return obstack_copy0 (&myobstack, addr, size);
228@}
229@end smallexample
230
231@noindent
232Contrast this with the previous example of @code{savestring} using
233@code{malloc} (@pxref{Basic Allocation, , , libc, The GNU C Library Reference Manual}).
234
235@node Freeing Obstack Objects
236@section Freeing Objects in an Obstack
237@cindex freeing (obstacks)
238
239To free an object allocated in an obstack, use the function
240@code{obstack_free}. Since the obstack is a stack of objects, freeing
241one object automatically frees all other objects allocated more recently
242in the same obstack.
243
244@comment obstack.h
245@comment GNU
246@deftypefun void obstack_free (struct obstack *@var{obstack-ptr}, void *@var{object})
247If @var{object} is a null pointer, everything allocated in the obstack
248is freed. Otherwise, @var{object} must be the address of an object
249allocated in the obstack. Then @var{object} is freed, along with
250everything allocated in @var{obstack} since @var{object}.
251@end deftypefun
252
253Note that if @var{object} is a null pointer, the result is an
254uninitialized obstack. To free all memory in an obstack but leave it
255valid for further allocation, call @code{obstack_free} with the address
256of the first object allocated on the obstack:
257
258@smallexample
259obstack_free (obstack_ptr, first_object_allocated_ptr);
260@end smallexample
261
262Recall that the objects in an obstack are grouped into chunks. When all
263the objects in a chunk become free, the obstack library automatically
264frees the chunk (@pxref{Preparing for Obstacks}). Then other
265obstacks, or non-obstack allocation, can reuse the space of the chunk.
266
267@node Obstack Functions
268@section Obstack Functions and Macros
269@cindex macros
270
271The interfaces for using obstacks may be defined either as functions or
272as macros, depending on the compiler. The obstack facility works with
273all C compilers, including both @w{ISO C} and traditional C, but there are
274precautions you must take if you plan to use compilers other than GNU C.
275
276If you are using an old-fashioned @w{non-ISO C} compiler, all the obstack
277``functions'' are actually defined only as macros. You can call these
278macros like functions, but you cannot use them in any other way (for
279example, you cannot take their address).
280
281Calling the macros requires a special precaution: namely, the first
282operand (the obstack pointer) may not contain any side effects, because
283it may be computed more than once. For example, if you write this:
284
285@smallexample
286obstack_alloc (get_obstack (), 4);
287@end smallexample
288
289@noindent
290you will find that @code{get_obstack} may be called several times.
291If you use @code{*obstack_list_ptr++} as the obstack pointer argument,
292you will get very strange results since the incrementation may occur
293several times.
294
295In @w{ISO C}, each function has both a macro definition and a function
296definition. The function definition is used if you take the address of the
297function without calling it. An ordinary call uses the macro definition by
298default, but you can request the function definition instead by writing the
299function name in parentheses, as shown here:
300
301@smallexample
302char *x;
303void *(*funcp) ();
304/* @r{Use the macro}. */
305x = (char *) obstack_alloc (obptr, size);
306/* @r{Call the function}. */
307x = (char *) (obstack_alloc) (obptr, size);
308/* @r{Take the address of the function}. */
309funcp = obstack_alloc;
310@end smallexample
311
312@noindent
313This is the same situation that exists in @w{ISO C} for the standard library
314functions. @xref{Macro Definitions, , , libc, The GNU C Library Reference Manual}.
315
316@strong{Warning:} When you do use the macros, you must observe the
317precaution of avoiding side effects in the first operand, even in @w{ISO C}.
318
319If you use the GNU C compiler, this precaution is not necessary, because
320various language extensions in GNU C permit defining the macros so as to
321compute each argument only once.
322
323@node Growing Objects
324@section Growing Objects
325@cindex growing objects (in obstacks)
326@cindex changing the size of a block (obstacks)
327
328Because memory in obstack chunks is used sequentially, it is possible to
329build up an object step by step, adding one or more bytes at a time to the
330end of the object. With this technique, you do not need to know how much
331data you will put in the object until you come to the end of it. We call
332this the technique of @dfn{growing objects}. The special functions
333for adding data to the growing object are described in this section.
334
335You don't need to do anything special when you start to grow an object.
336Using one of the functions to add data to the object automatically
337starts it. However, it is necessary to say explicitly when the object is
338finished. This is done with the function @code{obstack_finish}.
339
340The actual address of the object thus built up is not known until the
341object is finished. Until then, it always remains possible that you will
342add so much data that the object must be copied into a new chunk.
343
344While the obstack is in use for a growing object, you cannot use it for
345ordinary allocation of another object. If you try to do so, the space
346already added to the growing object will become part of the other object.
347
348@comment obstack.h
349@comment GNU
350@deftypefun void obstack_blank (struct obstack *@var{obstack-ptr}, int @var{size})
351The most basic function for adding to a growing object is
352@code{obstack_blank}, which adds space without initializing it.
353@end deftypefun
354
355@comment obstack.h
356@comment GNU
357@deftypefun void obstack_grow (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})
358To add a block of initialized space, use @code{obstack_grow}, which is
359the growing-object analogue of @code{obstack_copy}. It adds @var{size}
360bytes of data to the growing object, copying the contents from
361@var{data}.
362@end deftypefun
363
364@comment obstack.h
365@comment GNU
366@deftypefun void obstack_grow0 (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})
367This is the growing-object analogue of @code{obstack_copy0}. It adds
368@var{size} bytes copied from @var{data}, followed by an additional null
369character.
370@end deftypefun
371
372@comment obstack.h
373@comment GNU
374@deftypefun void obstack_1grow (struct obstack *@var{obstack-ptr}, char @var{c})
375To add one character at a time, use the function @code{obstack_1grow}.
376It adds a single byte containing @var{c} to the growing object.
377@end deftypefun
378
379@comment obstack.h
380@comment GNU
381@deftypefun void obstack_ptr_grow (struct obstack *@var{obstack-ptr}, void *@var{data})
382Adding the value of a pointer one can use the function
383@code{obstack_ptr_grow}. It adds @code{sizeof (void *)} bytes
384containing the value of @var{data}.
385@end deftypefun
386
387@comment obstack.h
388@comment GNU
389@deftypefun void obstack_int_grow (struct obstack *@var{obstack-ptr}, int @var{data})
390A single value of type @code{int} can be added by using the
391@code{obstack_int_grow} function. It adds @code{sizeof (int)} bytes to
392the growing object and initializes them with the value of @var{data}.
393@end deftypefun
394
395@comment obstack.h
396@comment GNU
397@deftypefun {void *} obstack_finish (struct obstack *@var{obstack-ptr})
398When you are finished growing the object, use the function
399@code{obstack_finish} to close it off and return its final address.
400
401Once you have finished the object, the obstack is available for ordinary
402allocation or for growing another object.
403
404This function can return a null pointer under the same conditions as
405@code{obstack_alloc} (@pxref{Allocation in an Obstack}).
406@end deftypefun
407
408When you build an object by growing it, you will probably need to know
409afterward how long it became. You need not keep track of this as you grow
410the object, because you can find out the length from the obstack just
411before finishing the object with the function @code{obstack_object_size},
412declared as follows:
413
414@comment obstack.h
415@comment GNU
416@deftypefun int obstack_object_size (struct obstack *@var{obstack-ptr})
417This function returns the current size of the growing object, in bytes.
418Remember to call this function @emph{before} finishing the object.
419After it is finished, @code{obstack_object_size} will return zero.
420@end deftypefun
421
422If you have started growing an object and wish to cancel it, you should
423finish it and then free it, like this:
424
425@smallexample
426obstack_free (obstack_ptr, obstack_finish (obstack_ptr));
427@end smallexample
428
429@noindent
430This has no effect if no object was growing.
431
432@cindex shrinking objects
433You can use @code{obstack_blank} with a negative size argument to make
434the current object smaller. Just don't try to shrink it beyond zero
435length---there's no telling what will happen if you do that.
436
437@node Extra Fast Growing
438@section Extra Fast Growing Objects
439@cindex efficiency and obstacks
440
441The usual functions for growing objects incur overhead for checking
442whether there is room for the new growth in the current chunk. If you
443are frequently constructing objects in small steps of growth, this
444overhead can be significant.
445
446You can reduce the overhead by using special ``fast growth''
447functions that grow the object without checking. In order to have a
448robust program, you must do the checking yourself. If you do this checking
449in the simplest way each time you are about to add data to the object, you
450have not saved anything, because that is what the ordinary growth
451functions do. But if you can arrange to check less often, or check
452more efficiently, then you make the program faster.
453
454The function @code{obstack_room} returns the amount of room available
455in the current chunk. It is declared as follows:
456
457@comment obstack.h
458@comment GNU
459@deftypefun int obstack_room (struct obstack *@var{obstack-ptr})
460This returns the number of bytes that can be added safely to the current
461growing object (or to an object about to be started) in obstack
462@var{obstack} using the fast growth functions.
463@end deftypefun
464
465While you know there is room, you can use these fast growth functions
466for adding data to a growing object:
467
468@comment obstack.h
469@comment GNU
470@deftypefun void obstack_1grow_fast (struct obstack *@var{obstack-ptr}, char @var{c})
471The function @code{obstack_1grow_fast} adds one byte containing the
472character @var{c} to the growing object in obstack @var{obstack-ptr}.
473@end deftypefun
474
475@comment obstack.h
476@comment GNU
477@deftypefun void obstack_ptr_grow_fast (struct obstack *@var{obstack-ptr}, void *@var{data})
478The function @code{obstack_ptr_grow_fast} adds @code{sizeof (void *)}
479bytes containing the value of @var{data} to the growing object in
480obstack @var{obstack-ptr}.
481@end deftypefun
482
483@comment obstack.h
484@comment GNU
485@deftypefun void obstack_int_grow_fast (struct obstack *@var{obstack-ptr}, int @var{data})
486The function @code{obstack_int_grow_fast} adds @code{sizeof (int)} bytes
487containing the value of @var{data} to the growing object in obstack
488@var{obstack-ptr}.
489@end deftypefun
490
491@comment obstack.h
492@comment GNU
493@deftypefun void obstack_blank_fast (struct obstack *@var{obstack-ptr}, int @var{size})
494The function @code{obstack_blank_fast} adds @var{size} bytes to the
495growing object in obstack @var{obstack-ptr} without initializing them.
496@end deftypefun
497
498When you check for space using @code{obstack_room} and there is not
499enough room for what you want to add, the fast growth functions
500are not safe. In this case, simply use the corresponding ordinary
501growth function instead. Very soon this will copy the object to a
502new chunk; then there will be lots of room available again.
503
504So, each time you use an ordinary growth function, check afterward for
505sufficient space using @code{obstack_room}. Once the object is copied
506to a new chunk, there will be plenty of space again, so the program will
507start using the fast growth functions again.
508
509Here is an example:
510
511@smallexample
512@group
513void
514add_string (struct obstack *obstack, const char *ptr, int len)
515@{
516 while (len > 0)
517 @{
518 int room = obstack_room (obstack);
519 if (room == 0)
520 @{
521 /* @r{Not enough room. Add one character slowly,}
522 @r{which may copy to a new chunk and make room.} */
523 obstack_1grow (obstack, *ptr++);
524 len--;
525 @}
526 else
527 @{
528 if (room > len)
529 room = len;
530 /* @r{Add fast as much as we have room for.} */
531 len -= room;
532 while (room-- > 0)
533 obstack_1grow_fast (obstack, *ptr++);
534 @}
535 @}
536@}
537@end group
538@end smallexample
539
540@node Status of an Obstack
541@section Status of an Obstack
542@cindex obstack status
543@cindex status of obstack
544
545Here are functions that provide information on the current status of
546allocation in an obstack. You can use them to learn about an object while
547still growing it.
548
549@comment obstack.h
550@comment GNU
551@deftypefun {void *} obstack_base (struct obstack *@var{obstack-ptr})
552This function returns the tentative address of the beginning of the
553currently growing object in @var{obstack-ptr}. If you finish the object
554immediately, it will have that address. If you make it larger first, it
555may outgrow the current chunk---then its address will change!
556
557If no object is growing, this value says where the next object you
558allocate will start (once again assuming it fits in the current
559chunk).
560@end deftypefun
561
562@comment obstack.h
563@comment GNU
564@deftypefun {void *} obstack_next_free (struct obstack *@var{obstack-ptr})
565This function returns the address of the first free byte in the current
566chunk of obstack @var{obstack-ptr}. This is the end of the currently
567growing object. If no object is growing, @code{obstack_next_free}
568returns the same value as @code{obstack_base}.
569@end deftypefun
570
571@comment obstack.h
572@comment GNU
573@deftypefun int obstack_object_size (struct obstack *@var{obstack-ptr})
574This function returns the size in bytes of the currently growing object.
575This is equivalent to
576
577@smallexample
578obstack_next_free (@var{obstack-ptr}) - obstack_base (@var{obstack-ptr})
579@end smallexample
580@end deftypefun
581
582@node Obstacks Data Alignment
583@section Alignment of Data in Obstacks
584@cindex alignment (in obstacks)
585
586Each obstack has an @dfn{alignment boundary}; each object allocated in
587the obstack automatically starts on an address that is a multiple of the
588specified boundary. By default, this boundary is 4 bytes.
589
590To access an obstack's alignment boundary, use the macro
591@code{obstack_alignment_mask}, whose function prototype looks like
592this:
593
594@comment obstack.h
595@comment GNU
596@deftypefn Macro int obstack_alignment_mask (struct obstack *@var{obstack-ptr})
597The value is a bit mask; a bit that is 1 indicates that the corresponding
598bit in the address of an object should be 0. The mask value should be one
599less than a power of 2; the effect is that all object addresses are
600multiples of that power of 2. The default value of the mask is 3, so that
601addresses are multiples of 4. A mask value of 0 means an object can start
602on any multiple of 1 (that is, no alignment is required).
603
604The expansion of the macro @code{obstack_alignment_mask} is an lvalue,
605so you can alter the mask by assignment. For example, this statement:
606
607@smallexample
608obstack_alignment_mask (obstack_ptr) = 0;
609@end smallexample
610
611@noindent
612has the effect of turning off alignment processing in the specified obstack.
613@end deftypefn
614
615Note that a change in alignment mask does not take effect until
616@emph{after} the next time an object is allocated or finished in the
617obstack. If you are not growing an object, you can make the new
618alignment mask take effect immediately by calling @code{obstack_finish}.
619This will finish a zero-length object and then do proper alignment for
620the next object.
621
622@node Obstack Chunks
623@section Obstack Chunks
624@cindex efficiency of chunks
625@cindex chunks
626
627Obstacks work by allocating space for themselves in large chunks, and
628then parceling out space in the chunks to satisfy your requests. Chunks
629are normally 4096 bytes long unless you specify a different chunk size.
630The chunk size includes 8 bytes of overhead that are not actually used
631for storing objects. Regardless of the specified size, longer chunks
632will be allocated when necessary for long objects.
633
634The obstack library allocates chunks by calling the function
635@code{obstack_chunk_alloc}, which you must define. When a chunk is no
636longer needed because you have freed all the objects in it, the obstack
637library frees the chunk by calling @code{obstack_chunk_free}, which you
638must also define.
639
640These two must be defined (as macros) or declared (as functions) in each
641source file that uses @code{obstack_init} (@pxref{Creating Obstacks}).
642Most often they are defined as macros like this:
643
644@smallexample
645#define obstack_chunk_alloc malloc
646#define obstack_chunk_free free
647@end smallexample
648
649Note that these are simple macros (no arguments). Macro definitions with
650arguments will not work! It is necessary that @code{obstack_chunk_alloc}
651or @code{obstack_chunk_free}, alone, expand into a function name if it is
652not itself a function name.
653
654If you allocate chunks with @code{malloc}, the chunk size should be a
655power of 2. The default chunk size, 4096, was chosen because it is long
656enough to satisfy many typical requests on the obstack yet short enough
657not to waste too much memory in the portion of the last chunk not yet used.
658
659@comment obstack.h
660@comment GNU
661@deftypefn Macro int obstack_chunk_size (struct obstack *@var{obstack-ptr})
662This returns the chunk size of the given obstack.
663@end deftypefn
664
665Since this macro expands to an lvalue, you can specify a new chunk size by
666assigning it a new value. Doing so does not affect the chunks already
667allocated, but will change the size of chunks allocated for that particular
668obstack in the future. It is unlikely to be useful to make the chunk size
669smaller, but making it larger might improve efficiency if you are
670allocating many objects whose size is comparable to the chunk size. Here
671is how to do so cleanly:
672
673@smallexample
674if (obstack_chunk_size (obstack_ptr) < @var{new-chunk-size})
675 obstack_chunk_size (obstack_ptr) = @var{new-chunk-size};
676@end smallexample
677
678@node Summary of Obstacks
679@section Summary of Obstack Functions
680
681Here is a summary of all the functions associated with obstacks. Each
682takes the address of an obstack (@code{struct obstack *}) as its first
683argument.
684
685@table @code
686@item void obstack_init (struct obstack *@var{obstack-ptr})
687Initialize use of an obstack. @xref{Creating Obstacks}.
688
689@item void *obstack_alloc (struct obstack *@var{obstack-ptr}, int @var{size})
690Allocate an object of @var{size} uninitialized bytes.
691@xref{Allocation in an Obstack}.
692
693@item void *obstack_copy (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
694Allocate an object of @var{size} bytes, with contents copied from
695@var{address}. @xref{Allocation in an Obstack}.
696
697@item void *obstack_copy0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
698Allocate an object of @var{size}+1 bytes, with @var{size} of them copied
699from @var{address}, followed by a null character at the end.
700@xref{Allocation in an Obstack}.
701
702@item void obstack_free (struct obstack *@var{obstack-ptr}, void *@var{object})
703Free @var{object} (and everything allocated in the specified obstack
704more recently than @var{object}). @xref{Freeing Obstack Objects}.
705
706@item void obstack_blank (struct obstack *@var{obstack-ptr}, int @var{size})
707Add @var{size} uninitialized bytes to a growing object.
708@xref{Growing Objects}.
709
710@item void obstack_grow (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
711Add @var{size} bytes, copied from @var{address}, to a growing object.
712@xref{Growing Objects}.
713
714@item void obstack_grow0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})
715Add @var{size} bytes, copied from @var{address}, to a growing object,
716and then add another byte containing a null character. @xref{Growing
717Objects}.
718
719@item void obstack_1grow (struct obstack *@var{obstack-ptr}, char @var{data-char})
720Add one byte containing @var{data-char} to a growing object.
721@xref{Growing Objects}.
722
723@item void *obstack_finish (struct obstack *@var{obstack-ptr})
724Finalize the object that is growing and return its permanent address.
725@xref{Growing Objects}.
726
727@item int obstack_object_size (struct obstack *@var{obstack-ptr})
728Get the current size of the currently growing object. @xref{Growing
729Objects}.
730
731@item void obstack_blank_fast (struct obstack *@var{obstack-ptr}, int @var{size})
732Add @var{size} uninitialized bytes to a growing object without checking
733that there is enough room. @xref{Extra Fast Growing}.
734
735@item void obstack_1grow_fast (struct obstack *@var{obstack-ptr}, char @var{data-char})
736Add one byte containing @var{data-char} to a growing object without
737checking that there is enough room. @xref{Extra Fast Growing}.
738
739@item int obstack_room (struct obstack *@var{obstack-ptr})
740Get the amount of room now available for growing the current object.
741@xref{Extra Fast Growing}.
742
743@item int obstack_alignment_mask (struct obstack *@var{obstack-ptr})
744The mask used for aligning the beginning of an object. This is an
745lvalue. @xref{Obstacks Data Alignment}.
746
747@item int obstack_chunk_size (struct obstack *@var{obstack-ptr})
748The size for allocating chunks. This is an lvalue. @xref{Obstack Chunks}.
749
750@item void *obstack_base (struct obstack *@var{obstack-ptr})
751Tentative starting address of the currently growing object.
752@xref{Status of an Obstack}.
753
754@item void *obstack_next_free (struct obstack *@var{obstack-ptr})
755Address just after the end of the currently growing object.
756@xref{Status of an Obstack}.
757@end table
758