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1 /* Copyright (C) 1991,93,96,97,99,2000,2002,2012 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
3 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
4 with help from Dan Sahlin (dan@sics.se) and
5 commentary by Jim Blandy (jimb@ai.mit.edu);
6 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
7 and implemented by Roland McGrath (roland@ai.mit.edu).
8
9 The GNU C Library is free software; you can redistribute it and/or
10 modify it under the terms of the GNU Lesser General Public
11 License as published by the Free Software Foundation; either
12 version 2.1 of the License, or (at your option) any later version.
13
14 The GNU C Library is distributed in the hope that it will be useful,
15 but WITHOUT ANY WARRANTY; without even the implied warranty of
16 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
17 Lesser General Public License for more details.
18
19 You should have received a copy of the GNU Lesser General Public
20 License along with the GNU C Library; if not, see
21 <http://www.gnu.org/licenses/>. */
22
23 #ifdef HAVE_CONFIG_H
24 #include <config.h>
25 #endif
26
27 #undef __ptr_t
28 #define __ptr_t void *
29
30 #if defined (_LIBC)
31 # include <string.h>
32 # include <memcopy.h>
33 # include <stdlib.h>
34 #endif
35
36 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
37 # include <limits.h>
38 #endif
39
40 #define LONG_MAX_32_BITS 2147483647
41
42 #ifndef LONG_MAX
43 #define LONG_MAX LONG_MAX_32_BITS
44 #endif
45
46 #include <sys/types.h>
47
48 #undef memchr
49
50
51 /* Find the first occurrence of C in S. */
52 __ptr_t
53 __rawmemchr (s, c_in)
54 const __ptr_t s;
55 int c_in;
56 {
57 const unsigned char *char_ptr;
58 const unsigned long int *longword_ptr;
59 unsigned long int longword, magic_bits, charmask;
60 unsigned char c;
61
62 c = (unsigned char) c_in;
63
64 /* Handle the first few characters by reading one character at a time.
65 Do this until CHAR_PTR is aligned on a longword boundary. */
66 for (char_ptr = (const unsigned char *) s;
67 ((unsigned long int) char_ptr & (sizeof (longword) - 1)) != 0;
68 ++char_ptr)
69 if (*char_ptr == c)
70 return (__ptr_t) char_ptr;
71
72 /* All these elucidatory comments refer to 4-byte longwords,
73 but the theory applies equally well to 8-byte longwords. */
74
75 longword_ptr = (unsigned long int *) char_ptr;
76
77 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
78 the "holes." Note that there is a hole just to the left of
79 each byte, with an extra at the end:
80
81 bits: 01111110 11111110 11111110 11111111
82 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
83
84 The 1-bits make sure that carries propagate to the next 0-bit.
85 The 0-bits provide holes for carries to fall into. */
86
87 if (sizeof (longword) != 4 && sizeof (longword) != 8)
88 abort ();
89
90 #if LONG_MAX <= LONG_MAX_32_BITS
91 magic_bits = 0x7efefeff;
92 #else
93 magic_bits = ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
94 #endif
95
96 /* Set up a longword, each of whose bytes is C. */
97 charmask = c | (c << 8);
98 charmask |= charmask << 16;
99 #if LONG_MAX > LONG_MAX_32_BITS
100 charmask |= charmask << 32;
101 #endif
102
103 /* Instead of the traditional loop which tests each character,
104 we will test a longword at a time. The tricky part is testing
105 if *any of the four* bytes in the longword in question are zero. */
106 while (1)
107 {
108 /* We tentatively exit the loop if adding MAGIC_BITS to
109 LONGWORD fails to change any of the hole bits of LONGWORD.
110
111 1) Is this safe? Will it catch all the zero bytes?
112 Suppose there is a byte with all zeros. Any carry bits
113 propagating from its left will fall into the hole at its
114 least significant bit and stop. Since there will be no
115 carry from its most significant bit, the LSB of the
116 byte to the left will be unchanged, and the zero will be
117 detected.
118
119 2) Is this worthwhile? Will it ignore everything except
120 zero bytes? Suppose every byte of LONGWORD has a bit set
121 somewhere. There will be a carry into bit 8. If bit 8
122 is set, this will carry into bit 16. If bit 8 is clear,
123 one of bits 9-15 must be set, so there will be a carry
124 into bit 16. Similarly, there will be a carry into bit
125 24. If one of bits 24-30 is set, there will be a carry
126 into bit 31, so all of the hole bits will be changed.
127
128 The one misfire occurs when bits 24-30 are clear and bit
129 31 is set; in this case, the hole at bit 31 is not
130 changed. If we had access to the processor carry flag,
131 we could close this loophole by putting the fourth hole
132 at bit 32!
133
134 So it ignores everything except 128's, when they're aligned
135 properly.
136
137 3) But wait! Aren't we looking for C, not zero?
138 Good point. So what we do is XOR LONGWORD with a longword,
139 each of whose bytes is C. This turns each byte that is C
140 into a zero. */
141
142 longword = *longword_ptr++ ^ charmask;
143
144 /* Add MAGIC_BITS to LONGWORD. */
145 if ((((longword + magic_bits)
146
147 /* Set those bits that were unchanged by the addition. */
148 ^ ~longword)
149
150 /* Look at only the hole bits. If any of the hole bits
151 are unchanged, most likely one of the bytes was a
152 zero. */
153 & ~magic_bits) != 0)
154 {
155 /* Which of the bytes was C? If none of them were, it was
156 a misfire; continue the search. */
157
158 const unsigned char *cp = (const unsigned char *) (longword_ptr - 1);
159
160 if (cp[0] == c)
161 return (__ptr_t) cp;
162 if (cp[1] == c)
163 return (__ptr_t) &cp[1];
164 if (cp[2] == c)
165 return (__ptr_t) &cp[2];
166 if (cp[3] == c)
167 return (__ptr_t) &cp[3];
168 #if LONG_MAX > 2147483647
169 if (cp[4] == c)
170 return (__ptr_t) &cp[4];
171 if (cp[5] == c)
172 return (__ptr_t) &cp[5];
173 if (cp[6] == c)
174 return (__ptr_t) &cp[6];
175 if (cp[7] == c)
176 return (__ptr_t) &cp[7];
177 #endif
178 }
179 }
180 }
181 libc_hidden_def (__rawmemchr)
182 weak_alias (__rawmemchr, rawmemchr)